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klio [65]
3 years ago
7

Tú creas una empresa de venta de camisetas estampadas. Encuentras que por un precio de $6 por cada camisa logras vender 1800 cam

isetas al mes. Si el precio de cada camiseta es de $8, solo logras vender 1450 camisetas. a. Presumiendo que el número de camisetas vendidas se puede modelar de forma lineal en función del precio de cada camiseta, determina la ecuación que modela el número total de camisetas vendidas en un mes. b. ¿Qué significa la pendiente en la ecuación? c. Tú dejas a un empleado encargado de la venta de las camisas. Este pone un precio y solo logró vender 1525 camisas. ¿Cuál fue el precio de las camisas?
Mathematics
1 answer:
Setler [38]3 years ago
7 0
Price= shirtsxcost
the change in cost of the shirt 
7$
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Evaluate the definite integral. <br> 1 x4(1 + 2x5)5 dx.
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Answer:

Step-by-step explanation:

Given the definite integral \int\limits {\dfrac{x^4}{(1-2x^5)^5} } \, dx, we to evaluate it. Using integration by substitution method.

Let u = 1-2x⁵ ...1

du/dx = -10x⁴

dx = du/-10x⁴.... 2

Substitute equation 1 and 2 into the integral function and evaluate the resulting integral as shown;

= \int\limits {\dfrac{x^4}{u^5} } \, \dfrac{du}{-10x^4}

= \dfrac{-1}{10} \int\limits {\dfrac{du}{u^5} }  \\\\= \dfrac{-1}{10} \int\limits {{u^{-5}du }  \\= \dfrac{-1}{10} [{\frac{u^{-5+1}}{-5+1}]  \\\\= \dfrac{-1}{10} ({\frac{u^{-4}}{-4})\\\\

= \dfrac{u^{-4}}{40} \\\\\\= \dfrac{1}{40u^4} +C

substitute u = 1-2x⁵ into the result

= \dfrac{1}{40(1-2x^5)^4} +C

Hence\int\limits {\dfrac{x^4}{(1-2x^5)^5} } \, dx = \dfrac{1}{40(1-2x^5)^4} +C

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3 years ago
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D

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The first and last sequence have a common difference in them. The first having d = 4 and the second having d = 7.

The second and third have a common ratio instead and are geometric sequences. The second has r = 2, and the third having r = (-3)

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Please help me !! :))))
mario62 [17]
I think a is your answer
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