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3 years ago

7

In the first quadrant you start at 5, 6 and move 4 units down. What point will you end up at? Thanks for your help! - Someone wh

o's better at English than math

1 answer:

Dmitrij [34]3 years ago

6 0

Answer:

(5, 2)

Step-by-step explanation:

(5, 6) go down 4 units means subtract 4 from the y

(5, 2)

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A round table has 4 legs and a rectangular table has 6 legs. If 10 tables have a total of 52 legs, how many of the legs belong t

ivolga24 [154]

Answer:

16 because if each chair has 4 legs you multiply that by the amount of chairs you have. 4x4=16

Step-by-step explanation:

4x4=16

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2 years ago

Choose the correct simplification of <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Ba%5E5b%5E6%7D%7Ba%5E4b%5E4%7D%20%20" id="Tex

Rashid [163]

The correct simplification will be: (b) ab²

$\frac{a^5 b^6}{a^4 b^4}$

Here we will use the property of exponents for division of two exponential terms with same bases. The original property is : $\frac{x^m}{x^n} = x^m^-^n$

It means if the bases are same , then we will just subtract the exponents while dividing two terms.

Using this property:

$\frac{a^5}{a^4} = a^5^-^4 = a^1 = a$

and $\frac{b^6}{b^4} = b^6^-^4 = b^2$

So, $\frac{a^5 b^6}{a^4 b^4} = ab^2$

3 0

3 years ago

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If i travel 300 miles in 2 hours what is my speed

avanturin [10]

Answer:

150 miles per hour

Step-by-step explanation:

Distance over time

miles = distance

hours = time

300/2 = 150 miles per hour

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3 years ago

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Write the equation of each line given the y-intercept and x-intercept.

dalvyx [7]

Answer:

y=-2/3x-2

Step-by-step explanation:

-2/3 is the slope and -2 is the y intercept

y=mx+b

m is slope and b is y intercept

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3 years ago

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A 500500-gallon tank initially contains 200200 gallons of brine containing 100100 pounds of dissolved salt. brine containing 11

mixer [17]

Let $A(t)$ denote the amount of salt in the tank at time $t$ . We're given that the tank initially holds $A(0)=100$ lbs of salt.

The rate at which salt flows in and out of the tank is given by the relation

$\dfrac{\mathrm dA}{\mathrm dt}=\underbrace{\dfrac{11\text{ lb}}{1\text{ gal}}\times\dfrac{44\text{ gal}}{1\text{ min}}}_{\text{rate in}}-\underbrace{\dfrac{A(t)}{200+(44-11)t}\times\dfrac{11\text{ gal}}{1\text{ min}}}_{\text{rate out}}$
$\implies A'(t)+\dfrac{11}{200+33t}A(t)=484$

Find the integrating factor:

$\mu(t)=\exp\left(\displaystyle\int\frac{11}{200+33t}\,\mathrm dt\right)=(200+33t)^{1/3}$

Distribute $\mu(t)$ along both sides of the ODE:

$(200+33t)^{1/3}A'(t)+11(200+33t)^{-2/3}A(t)=484(200+33t)^{-1/3}$
$\bigg((200+33t)^{1/3}A(t)\bigg)'=484(200+33t)^{-1/3}$
$A(t)=484\displaystyle\int(200+33t)^{-1/3}\,\mathrm dt$
$A(t)=22(200+33t)^{2/3}+C$

Since $A(0)=100$ , we get

$100=22(200)^{2/3}+C\implies C\approx-652.39$

so that the particular solution for $A(t)$ is

$A(t)=22(200+33t)^{2/3}-652.39$

The tank becomes full when the volume of solution in the tank at time $t$ is the same as the total volume of the tank:

$200+(44-11)t=500\implies 33t=300\implies t\approx9.09$

at which point the amount of salt in the solution would be

$A(9.09)\approx733.47\text{ lb}$

4 0

3 years ago