Answer:
C
Step-by-step explanation:
Answer:
29/28
Step-by-step explanation:
![- \frac{2}{7} \times ( - 3 \frac{5}{8} ) \\ - \frac{2}{7} \times ( - \frac{29}{8} ) \\](https://tex.z-dn.net/?f=%20-%20%20%5Cfrac%7B2%7D%7B7%7D%20%20%5Ctimes%20%28%20-%203%20%5Cfrac%7B5%7D%7B8%7D%20%29%20%5C%5C%20%20-%20%20%5Cfrac%7B2%7D%7B7%7D%20%20%5Ctimes%20%28%20-%20%20%5Cfrac%7B29%7D%7B8%7D%20%29%20%5C%5C%20)
![= \frac{29}{28}](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B29%7D%7B28%7D%20)
Answer:
Acceleration of the particle = ![bw^{2}](https://tex.z-dn.net/?f=bw%5E%7B2%7D)
Step-by-step explanation:
We are given the position vector of a particle moving in a circle of radius b units.
r(t) = b cos(ωt)i + b sin(ωt)j
Velocity , v =
= -bω sin(ωt)i + bω cos(ωt)j
The magnitude of velocity, v =![\sqrt{v_x^{2} +v_y^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7Bv_x%5E%7B2%7D%20%2Bv_y%5E%7B2%7D%20%7D)
Squaring both sides,
![v^{2} = b^{2} w^{2}(sin^{2}(wt)+cos^{2}(wt))](https://tex.z-dn.net/?f=v%5E%7B2%7D%20%3D%20b%5E%7B2%7D%20w%5E%7B2%7D%28sin%5E%7B2%7D%28wt%29%2Bcos%5E%7B2%7D%28wt%29%29)
Since
= 1
![v^{2} = b^{2}w^{2}](https://tex.z-dn.net/?f=v%5E%7B2%7D%20%3D%20b%5E%7B2%7Dw%5E%7B2%7D)
The acceleration towards the centre is called the centripetal acceleration and is given by
a = ![\frac{v^{2} }{r}](https://tex.z-dn.net/?f=%5Cfrac%7Bv%5E%7B2%7D%20%7D%7Br%7D)
a = ![\frac{b^{2}w^{2}}{b}](https://tex.z-dn.net/?f=%5Cfrac%7Bb%5E%7B2%7Dw%5E%7B2%7D%7D%7Bb%7D)
a = ![bw^{2}](https://tex.z-dn.net/?f=bw%5E%7B2%7D)
Answer:
b
Step-by-step explanation: