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3 years ago

Which value of x makes it true

Mathematics

1 answer:

son4ous [18]3 years ago

8 0

Answer:

i think its...

answer: B

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-6+ (-20) + (-40) + 3d

cupoosta [38]

Answer:

-3(22-d) ?

Step-by-step explanation:

I hope this is right please let me know

8 0

2 years ago

Pls anyone help need help

Neko [114]

Answer:

- 2 ≤ n < 8

Step-by-step explanation:

The closed circle at - 2 indicates that n can equal - 2

The open circle at 8 indicates that n cannot equal 8

Otherwise n can be all value between - 2 and 8 including - 2, thus

- 2 ≤ n < 8

3 0

3 years ago

Select all the statements that correctly describe the solutions to this system of equations?

Luba_88 [7]

x + y = 9

x = 9 - y

2x - y = 0

2(9 - y) - y = 0

18 - 2y - y = 0

-3y = -18

y = 6

x = 9 - y

x = 9 - 6

x = 3

5 0

2 years ago

What are all of the real roots of the following polynomial? f(x) = x4 - 13x2 + 36

GREYUIT [131]

ANSWER

A. -3, -2, 2, and 3

EXPLANATION

The given polynomial function is,

$f(x) = {x}^{4} - 13 {x}^{2} + 36$

To find the real roots, we equate the function to zero to obtain;

${x}^{4} - 13 {x}^{2} + 36 = 0$

We can solve this equation as a quadratic equation in
${x}^{2}.$

Thus we rewrite the equation as,

$({x}^{2})^{2} - 13 {x}^{2} + 36 = 0$

We split the middle term to get,

$({x}^{2})^{2} - 9 {x}^{2} - 4 {x}^{2} + 36 = 0.$

We factor to get,

${x}^{2} ( {x}^{2} - 9) - 4( {x}^{2} - 9) = 0$

We factor to get,

$( {x}^{2} - 9)( {x}^{2} - 4) = 0$

Either

${x}^{2} - 9 = 0$
or

${x}^{2} - 4 = 0$

$x = \pm \sqrt{9} \: or \: x = \pm \sqrt{4}$
$x = \pm3 \: or \: x = \pm2$

$x=-3,-2,2,3$

The correct answer is A

5 0

3 years ago

Read 2 more answers

What percent of the

Fed [463]

1.5/4 is shaded, since there is one block shaded, and half of another block (1.5)

6 0

2 years ago

Read 2 more answers