Jason's scores : 80 90 95 85 70 and
Jill's score : 70 75 90 100 95.
Mean of Jason's scores = 
Mean of Jill's scores = 
Now, in order to find the mean absolute deviation, need to find the difference of each score from means.
<u>Mean absolute deviation for Jason's scores.</u>
|84-80| = 4
|84-90| = 6
|84-95| = 9
|84-85| = 1
|84-70|= 14
<u>Mean absolute deviation for Jill's scores</u>
|86-70| = 16
|86-75| = 11
|86-90| = 4
|86-100| = 14
|86-95|= 9
Jill got average quiz score 86 and Jason got 84.
Therefore, Jill got better quiz average.
Also, the mean absolute deviation for Jason scores is less that is 6.8 than 10.8.
Therefore, Jason got more consistent grades.
3:8 - 3:8
8:6 - 4:3
4:8 - 1:2
I would say that the answer is 1:2
yes because if you look you can see a pattern of 4 if we divide 2 AND 8 WE GET 4 AND SO.
First example:
Subtract the 8n on both sides to get the variable on one side of the equation. Do the same for the regular numbers. Then divide by -3.
This should be your final answer.
Second Example:
Do the same thing as explained in Example 1. Here's some work to help guide you.
That should be your final answer here.
Third Example:
Hope this helps and its understandable! Let me know if you still don't understand.
Answer:
J'(2, 1)
K'(0, 3)
Step-by-step explanation:
On a coordinate plane, coordinates of the points J, K and L are (-2, 1), (0, 3) and (2, -1) respectively.
If we reflect these points over the line x = 0 or y-axis, rule to be followed is
(x, y) → (-x, y)
Only sign of x coordinates get changed while y coordinates remain the same.
Following this rule coordinates of the images of J' and K' will be
J(-2, 1) → J'(2, 1)
and K(0, 3) → K'(0, 3)
