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3 years ago

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If you get this you can have 32 points!!!! just please help no wrong answers please.Last Question please help :) <3 Thank you

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1 answer:

spin [16.1K]3 years ago

6 0

Your answer would be 25

You might be interested in

Please help this is i-ready!

KengaRu [80]

Answer: It will take 3 days.

Step-by-step explanation:

1 km = 1000m

12 km = 12,000m

10 * 400m = 4000m

12,000m / 1000m = 3

So, It will take 3 Days.

I hope I helped you with this I-Ready. Have a Great day!

3 0

3 years ago

Read 2 more answers

For two events A and B show that P (A∩B) ≥ P (A)+P (B)−1.

nordsb [41]

Answer:

<h3>For two events A and B show that P (A∩B) ≥ P (A)+P (B)−1.</h3>

By De morgan's law

$(A\cap B)^{c}=A^{c}\cup B^{c}\\\\P((A\cap B)^{c})=P(A^{c}\cup B^{c})\leq P(A^{c})+P(B^{c}) \\\\1-P(A\cap B)\leq P(A^{c})+P(B^{c}) \\\\1-P(A\cap B)\leq 1-P(A)+1-P(B)\\\\-P(A\cap B)\leq 1-P(A)-P(B)\\\\P(A\cap B)\geq P(A)+P(B)-1$

which is Bonferroni’s inequality

<h3>Result 1: P (Ac) = 1 − P(A)</h3>

Proof

If S is universal set then

$A\cup A^{c}=S\\\\P(A\cup A^{c})=P(S)\\\\P(A)+P(A^{c})=1\\\\P(A^{c})=1-P(A)$

<h3>Result 2 : For any two events A and B, P (A∪B) = P (A)+P (B)−P (A∩B) and P(A) ≥ P(B)</h3>

Proof:

If S is a universal set then:

$A\cup(B\cap A^{c})=(A\cup B) \cap (A\cup A^{c})\\=(A\cup B) \cap S\\A\cup(B\cap A^{c})=(A\cup B)$

Which show A∪B can be expressed as union of two disjoint sets.

If A and (B∩Ac) are two disjoint sets then

$P(A\cup B) =P(A) + P(B\cap A^{c})---(1)\\$

B can be expressed as:

$B=B\cap(A\cup A^{c})\\$

If B is intersection of two disjoint sets then

$P(B)=P(B\cap(A)+P(B\cup A^{c})\\P(B\cup A^{c}=P(B)-P(B\cap A)$

Then (1) becomes

$P(A\cup B) =P(A) +P(B)-P(A\cap B)\\$

<h3>Result 3: For any two events A and B, P(A) = P(A ∩ B) + P (A ∩ Bc)</h3>

Proof:

If A and B are two disjoint sets then

$A=A\cap(B\cup B^{c})\\A=(A\cap B) \cup (A\cap B^{c})\\P(A)=P(A\cap B) + P(A\cap B^{c})\\$

<h3>Result 4: If B ⊂ A, then A∩B = B. Therefore P (A)−P (B) = P (A ∩ Bc) </h3>

Proof:

If B is subset of A then all elements of B lie in A so A ∩ B =B

$A =(A \cap B)\cup (A\cap B^{c}) = B \cup ( A\cap B^{c})$

where A and A ∩ Bc are disjoint.

$P(A)=P(B\cup ( A\cap B^{c}))\\\\P(A)=P(B)+P( A\cap B^{c})$

From axiom P(E)≥0

$P( A\cap B^{c})\geq 0\\\\P(A)-P(B)=P( A\cap B^{c})\\P(A)=P(B)+P(A\cap B^{c})\geq P(B)$

Therefore,

P(A)≥P(B)

8 0

3 years ago

A soda manufacturer claims that on average their bottles contain 16oz of soda with an SD of 0.1oz. A regulatory agency decides t

vova2212 [387]

Answer: The chances are of the probability = 0.0001

Step-by-step explanation:

The normal distribution can be described completely by the two parameters µ and σ.

As always, the mean is the center of the distribution and the standard deviation is the measure of the variation around the mean.

Please find the attached file for the solution

4 0

3 years ago

*PICTURE ATTACHED* please help

KIM [24]

Answer:

Step-by-step explanation:

10^0=1

10^-3 = 1/10^3

4.0=4

so : 1.72×10^0/4.0×10^-3 = (1.72× 10^3)/4 =430

scientific notation is : 4.30× 10^2

4 0

3 years ago

The distance from Jacksonville to Tampa is 171 miles. The distance from Tampa to Miami is 206 miles. Use the triangle inequality

Natali [406]

The triangle inequality theorem states that any side of a triangle is always shorter than the sum of the two other sides.
That means if you add up the distance from jacksonville to tampa and the distane from tampa to miami, the distance from jacksonville to miami must be less than that.

171 miles + 206 miles = 377 miles

the distance from jacksonville to miami must be less than 377 miles

3 0

3 years ago