The arrow below was painted in a school parking lot. What is the area of the arrow?

Mathematics

2 answers:

Vladimir [108]3 years ago

7 0

Answer:

no se ablar inglés losiento

algol [13]3 years ago

3 0

Answer: 16ft^2

Step-by-step explanation:

You have to split this arrow into 2 shapes; a triangle and a rectangle.

To work out the area of the rectangle you would do 2x6=12

Then to work out the area of the triangle you would have to do 2+1+1=4 (this is the base, b, of the triangle).

To work out the height, h, of the triangle you have to do 8-6=2

The formula for the area of the triangle is bxh/2 which is 4x2/2= 4

Then you have to add the area of the triangle and the rectangle (12+4=16)

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Cody has $700 in a savings account that pays 4% simple interest. how much will he have in one year

Vlada [557]

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7 0

3 years ago

Which statements are true about the graph of the function f(x) = x2 – 8x + 5? Check all that apply.

statuscvo [17]

Answer:

A, D, E are true

Step-by-step explanation:

You have to complete the square to prove A. Do this by first setting the function equal to 0, then moving the 5 to the other side.

$x^2-8x=-5$

Now we can complete the square. Take half the linear term, square it, and add it to both sides. Our linear term is 8 (from the -8x). Half of 8 is 4, and 4 squared is 16. So we add 16 to both sides.

$(x^2-8x+16)=-5+16$

We will do the addition on the right, no big deal. On the left, however, what we have done in the process of completing the square is to create a perfect square binomial, which gives us the h coordinate of the vertex. We will rewrite with that perfect square on the left and the addition done on the right,

$(x-4)^2=11$

Now we will move the 11 back over, which gives us the k coordinate of the vertex.

$(x-4)^2-11=y$

From this you can see that A is correct.

Also we can see that the vertex of this parabola is (4, -11), which is why B is NOT correct.

The axis of symmetry is also found in the h value. This is, by definition, a positive x-squared parabola (opens upwards), so its axis of symmetry will be an "x = " equation. In the case of this type of parabola, that "x = " will always be equal to the h value. So the axis of symmetry is

x = 4, which is why C is NOT correct, either.

We can find the y-intercept of the function by going back to the standard form of the parabola (NOT the vertex form we found by completing the square) and sub in a 0 for x. When we do that, and then solve for y, we find that when x = 0, y = 5. So the y-intercept is (0, 5).

From this you can see that D is also correct.

To determine if the parabola has real solutions (meaning it will go through the x-axis twice), you can plug it into the quadratic formula to find these values of x. I just plugged the formula into my graphing calculator and graphed it to see that it did, indeed, go through the x-axis twice. Just so you know, the values of x where the function go through are (.6833752, 0) and (7.3166248, 0). That's why you need the quadratic formula to find these values.

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3 years ago

Find the product of<br> (x2 + 3x + 1)(x2 + x + 2)

Bogdan [553]

Answer: $x^4+4x^3+6x^2+7x+2$