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miv72 [106K]
3 years ago
9

The arrow below was painted in a school parking lot. What is the area of the arrow?

Mathematics
2 answers:
Vladimir [108]3 years ago
7 0

Answer:

no se ablar inglés losiento

algol [13]3 years ago
3 0

Answer: 16ft^2

Step-by-step explanation:

You have to split this arrow into 2 shapes; a triangle and a rectangle.

To work out the area of the rectangle you would do 2x6=12

Then to work out the area of the triangle you would have to do 2+1+1=4 (this is the base, b, of the triangle).

To work out the height, h, of the triangle you have to do 8-6=2

The formula for the area of the triangle is bxh/2 which is 4x2/2= 4

Then you have to add the area of the triangle and the rectangle (12+4=16)

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3 years ago
the 11th term in a geometric sequence is 48 and the common ratio is 4. the 12th term is 192 and the 10th term is what?
Soloha48 [4]

<u>Given</u>:

The 11th term in a geometric sequence is 48.

The 12th term in the sequence is 192.

The common ratio is 4.

We need to determine the 10th term of the sequence.

<u>General term:</u>

The general term of the geometric sequence is given by

a_n=a(r)^{n-1}

where a is the first term and r is the common ratio.

The 11th term is given is

a_{11}=a(4)^{11-1}

48=a(4)^{10} ------- (1)

The 12th term is given by

192=a(4)^{11} ------- (2)

<u>Value of a:</u>

The value of a can be determined by solving any one of the two equations.

Hence, let us solve the equation (1) to determine the value of a.

Thus, we have;

48=a(1048576)

Dividing both sides by 1048576, we get;

\frac{3}{65536}=a

Thus, the value of a is \frac{3}{65536}

<u>Value of the 10th term:</u>

The 10th term of the sequence can be determined by substituting the values a and the common ratio r in the general term a_n=a(r)^{n-1}, we get;

a_{10}=\frac{3}{65536}(4)^{10-1}

a_{10}=\frac{3}{65536}(4)^{9}

a_{10}=\frac{3}{65536}(262144)

a_{10}=\frac{786432}{65536}

a_{10}=12

Thus, the 10th term of the sequence is 12.

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Answer:

x=3/2

Step-by-step explanation:

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