hi whats the answer ill give brainlist

Mathematics

1 answer:

Sonbull [250]3 years ago

6 0

Answer:

the last option

Step-by-step explanation:

see my explanation in the comments! :)

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I will be honest I'm having a major brain fart.. What's the line called and what's it do again? it's separating numbers.. Looks

Alla [95]

Answer:

fraction bar. separates numerator and denominator in a fraction

5 0

3 years ago

Solve the equation, if possible.

Shalnov [3]

Answer:

no solution

Step-by-step explanation:

Given

- 3 | 6n - 2 | + 5 = 8 ( subtract 5 from both sides )

- 3 | 6n - 2 | = 3 ( divide both sides by - 3 )

| 6n - 2 | = - 1

The absolute value always returns a positive value and so

| 6n - 2 | ≠ - 1

Hence there is no solution to the equation

4 0

3 years ago

A company must select 4 candidates to interview from a list of 12, which consist of 8 men and 4 women.

Radda [10]

Part A

If 4 candidates were to be selected regardless of gender, that means that 4 candidates is to be selected from 12.

The number of possible selections of 4 candidates from 12 is given by

$^{12}C_4= \frac{12!}{4!(12-4)!}= \frac{12!}{4!\times8!} =11\times5\times9=495$

Therefore, the number of selections of 4 candidates regardless of gender is 495.

Part B:


If 4 candidates were to be selected such that 2 women must be selected, that means that 2 men candidates is to be selected from 8 and 2 women candidates is to be selected from 4.

The number of possible selections of 2 men candidates from 8 and 2 women candidates from 4 is given by

 $^{8}C_2\times ^{4}C_2= \frac{8!}{2!(8-2)!}\times 
\frac{4!}{2!(4-2)!} \\ \\ = 
\frac{8!}{2!\times6!}\times\frac{4!}{2!\times2!} 
=4\times7\times2\times3=168$

Therefore, the number of selections of 4 candidates such that 2 women must be selected is 168.

Part 3:

If 4 candidates were to be selected such that at least 2 women must be selected, that means that 2 men candidates is to be selected from 8 and 2 women candidates is to be selected from 4 or 1 man candidates is to be selected from 8 and 3 women candidates is to be selected from 4 of no man candidates is to be selected from 8 and 4 women candidates is to be selected from 4.

The number of possible selections of 2 men candidates from 8 and 2 women candidates from 4 of 1 man candidates from 8 and 3 women candidates from 4 of no man candidates from 8 and 4 women candidates from 4 is given by

$^{8}C_2\times ^{4}C_2+ ^{8}C_1\times ^{4}C_3+ ^{8}C_0\times ^{4}C_4 \\ \\ = \frac{8!}{2!(8-2)!}\times \frac{4!}{2!(4-2)!}+\frac{8!}{1!(8-1)!}\times \frac{4!}{3!(4-3)!}+\frac{8!}{0!(8-0)!}\times \frac{4!}{4!(4-4)!} \\ \\ = \frac{8!}{2!\times6!}\times\frac{4!}{2!\times2!}+\frac{8!}{1!\times7!}\times\frac{4!}{3!\times1!}+\frac{8!}{0!\times8!}\times\frac{4!}{4!\times0!} \\ \\ =4\times7\times2\times3+8\times4+1\times1=168+32+1=201$

Therefore, the number of selections of 4 candidates such that at least 2 women must be selected is 201.

7 0

3 years ago

Read 2 more answers

write an equation of a line that is perpendicular to the given line and that passes through the given point (4,-6); m=3/5

tresset_1 [31]

Answer:

$y=-\frac{5}{3} x-\frac{42}{5}$

Step-by-step explanation:

Given the slope and another point, simply plug them into the point-slope formula to find your y-intercept.

$y-y1=m(x-x1)\\y-(-6)=\frac{3}{5} (x-4)\\y+6=\frac{3}{5} x-\frac{12}{5} \\y=\frac{3}{5} x-\frac{42}{5}$

Now that we've found your y-intercept, we have the original equation. To find the perpendicular equation, you need the opposite reciprocal of your slope.

To find the 'opposite,' change your slope's sign. Since your slope is positive $\frac{3}{5}$ , the opposite is $-\frac{3}{5}$ .