Question

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Answer 1

Answer:

$\boxed{ \sf Obtuse \ triangle}$

Explanation:

We can check if the triangle is a right triangle or not by using Pythagorean theorem.

$c=\sqrt{a^2 +b^2 }$

$6=\sqrt{3^2 +4^2 }$

$6=\sqrt{9+16 }$

$6=\sqrt{25 }$

$6=5$

The triangle is not a right triangle.

When $c>\sqrt{a^2 +b^2 }$, the triangle is an obtuse triangle.

Answer 2

Answer:

$\boxed{\sf Obtuse \ Angled \ Triangle}$

Explanation:

Let's check it by Pythagorean theorem:

$\sf c^2 = a^2+b^2$

Where c = 6, a = 4 and b = 3

$\sf (6)^2= (4)^2+(3)^2$

$\sf 36 = 16+9$

$36 \neq 25$

But,

$\sf 36> 25$

When $\sf c^2 > a^2+b^2$, then the triangle is obtuse angled triangle.