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4 years ago

How can you tell from an equation that a relation is quadratic

Mathematics

1 answer:

monitta4 years ago

5 0

Answer:

if the equation is f(x)=ax^2+bx+c

Step-by-step explanation:

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According to the line Gregg below what is the total number of tickets sold ?

podryga [215]

Answer:

The answer would be 155 tickets

6 0

3 years ago

The baker at weis supermarket will cut 5 indeticial loaves of bread into pices that are 1/3 . After he cuts the 5 loaves how man

IrinaK [193]

Answer:

15 pieces

Step-by-step explanation:

we see if we get 3 pieces from one bread then 5 will be 15

hope it helps you

please mark me as brainlist

5 0

3 years ago

Read 2 more answers

Find the value of x to the nearest tenth

Hitman42 [59]

Answer:

a^2+b^2=c^2

6^2+6^2=72

square root of 72

=8.49(3sf)

c^2-b^2=a^2

x=3

5 0

3 years ago

Read 2 more answers

for a field trip, a bus company charges a flat fee plus an additional fee per student. For 40 students, the total cost is $250.0

swat32

Okay so 6.25 a student then it goes to 4.50 for 15 more students at 70 students its 358.75 now it drops another 1.75 so it would be 368.75 for 80 students so the equation is 4.48 x 80 = 368.75. enjoy :D

3 0

3 years ago

Suppose that in a random selection of 100 colored candies, 28% of them are blue. The candy company claims that the percentage

Zigmanuir [339]

Answer:

We conclude that the percentage of blue candies is equal to 29%.

Step-by-step explanation:

We are given that in a random selection of 100 colored candies, 28% of them are blue. The candy company claims that the percentage of blue candies is equal to 29%.

Let p = population percentage of blue candies

So, Null Hypothesis, $H_0$ : p = 29% {means that the percentage of blue candies is equal to 29%}

Alternate Hypothesis, $H_A$ : p $\neq$ 29% {means that the percentage of blue candies is different from 29%}

The test statistics that will be used here is One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of blue coloured candies = 28%

n = sample of colored candies = 100

So, the test statistics = $\frac{0.28-0.29}{\sqrt{\frac{0.29(1-0.29)}{100} } }$

= -0.22

The value of the z-test statistics is -0.22.

Also, the P-value of the test statistics is given by;

P-value = P(Z < -0.22) = 1 - P(Z $\leq$ 0.22)

= 1 - 0.5871 = 0.4129

Now, at a 0.10 level of significance, the z table gives a critical value of -1.645 and 1.645 for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of z, so we insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the percentage of blue candies is equal to 29%.

4 0

3 years ago