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2 years ago

I will give Brainliest AND a Cookie!

Mathematics

2 answers:

CaHeK987 [17]2 years ago

4 0

Answer:

Step-by-step explanation:

$\sqrt{25}$ =5 This means that it has the highest value

prohojiy [21]2 years ago

4 0

5 where my cookie at

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In a random sample of 7 residents of the state of California, the mean waste recycled per person per day was 1.5 pounds with a s

ale4655 [162]

Answer:

CI(99%) = ( 0.93 , 2.07)

Therefore at 99% confidence interval (a,b) = ( 0.93 , 2.07)

Critical value z(at 99% confidence) = z(0.005) = 2.58

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean gain x = 1.5

Standard deviation r = 0.58

Number of samples n = 7

Confidence interval = 99%

Critical value z(at 99% confidence) = z((1-0.99)/2)

z(0.005) = 2.58

Substituting the values we have;

1.5+/-2.58(0.58/√7)

1.5+/-2.58(0.2192)

1.5+/-0.565536

1.5+/-0.57

= ( 0.93 , 2.07)

Therefore at 99% confidence interval (a,b) = ( 0.93 , 2.07)

7 0

3 years ago

Solve using the linear combination method (show work)<br> 4 − 9 = 1 <br> −4 + 6 = −2

Scilla [17]

Did you type this incorrectly?

5 0

3 years ago

A manufacturer of running shoes knows that the average lifetime for a particular model of shoes is 15 months. Someone in the res

AveGali [126]

Answer:

The decision rule is

Fail to reject the null hypothesis

The conclusion is

There is no sufficient evidence to show that the designer's claim of a better shoe is supported by the trial results.

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 15 \ months$

The sample size is n = 25

The sample mean is $\= x = 17 \ months$

The standard deviation is $s = 5.5 \ months$

Let assume the level of significance of this test is $\alpha = 0.05$

The null hypothesis is $H_o : \mu = 15$

The alternative hypothesis is $H_a : \mu > 17$

Generally the degree of freedom is mathematically represented as

$df = n -1$

=> $df = 25 -1$

=> $df = 24$

Generally the test statistics is mathematically represented as

$t = \frac{\= x- \mu }{\frac{s}{\sqrt{n} } }$

=> $t = \frac{ 17 - 15 }{\frac{5.5}{\sqrt{25} } }$

=> $t = 1.8182$

Generally from the student t distribution table the probability of obtaining $t = 1.8182$ to the right of the curve at a degree of freedom of $df = 24$ is

$p-value = P(t > 0.18182 ) = 0.4286$

From the value obtained we see that $p-value > \alpha$ hence

The decision rule is

Fail to reject the null hypothesis

The conclusion is

There is no sufficient evidence to show that the designer's claim of a better shoe is supported by the trial results.

7 0

2 years ago

Use the data in the following table , which lists drive - thru order accuracy at popular fast food chains Assume that orders are

Elodia [21]

Answer:

Step-by-step explanation:

5 0

3 years ago

Find the limit as x approaches 0 for cos(2x) / x

zhenek [66]

We are asked to determine the limits of the function cos(2x) / x as x approaches to zero. In this case, we first substitute zero to x resulting to 1/0. A number, any number divided by zero is always equal to infinity, Hence there are no limits to this function.

5 0

3 years ago