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3 years ago

How can the font type of an existing style named No Spacing be changed?

Computers and Technology

2 answers:

sergejj [24]3 years ago

8 0

Answer: it depends on the font size

Explanation:

nirvana33 [79]3 years ago

3 0

Steps involved in changing the font type of an existing style named No Spacing:

In Word document, place a right click on any style in style gallery in the Home Tab.

Now a pop-up with many option appears .

Select Modify button from the pop-up

Modify style dialogue box appears

In the Modify style dialogue box, under the formatting section, the font style can be changed.

You can also change the font size by clicking on the format button in the left bottom corner of the modify style dialogue box.

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3 years ago

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3 years ago

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As a student, why do you need to know and follow the steps printing a document?

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3 years ago

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The cost to ship a package is a flat fee of 75 cents plus 25 cents per pound.

Sonbull [250]

Answer:

The following alterations are done to the program

1. Replace /* Your solution goes here */ with

const int CENTS_PER_POUND = 25;

cout<<"Ship Weight Pounds: ";

cin>>shipWeightPounds;

2. Include

shipCostCents = FLAT_FEE_CENTS + CENTS_PER_POUND * shipWeightPounds;

after

cout << ", Cents per lb: " << CENTS_PER_POUND;

Explanation:

See attachment for complete program as it should be ordered

This line declares CENTS_PER_POUND as a constant integer and it also initializes the variable to 25

const int CENTS_PER_POUND = 25;

This prompts the user for the weight of the shipping items (in pounds)

cout<<"Ship Weight Pounds: ";

This gets user input for the weight of the shipping item

cin>>shipWeightPounds;

.............................

........

...

This calculates the cost of shipping the item

shipCostCents = FLAT_FEE_CENTS + CENTS_PER_POUND * shipWeightPounds;

Download cpp

6 0

3 years ago

In which of the following is “y” not equal to 5 after execution? X is equal to 4.

Step2247 [10]

Answer:

d) y=x++

Explanation:

In all 3 statements:

y= ++x;

y=x=5;

y=5;

The value of y is equal to 5.

However in the statement y=x++, the value of 5 is equal to value of x prior to the increment operation. The original value of x was 4. So the value of y will be 4. Note that after the statement execution, the value of x will be updated to 5. In effect y=x++ can be visualized as a sequence of following steps:

x=4;

y=x;

x=x+1;

5 0

3 years ago