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kramer
3 years ago
9

An airline wants to select a computer software package for its reservation system. Four software packages (1, 2, 3, and 4) are c

ommercially available. The airline will choose the package that bumps as few passengers as possible during a month. An experiment is set up in which each package is used to make reservations for 5 randomly selected weeks. (A total of 20 weeks was included in the experiment.) The number of passengers bumped each week is obtained, which gives rise to the following Excel output:
ANOVA
Source of Variation SS df MS F P-value F crit
Between Groups 212.4 3 8.304985 0.001474 3.238867
Within Groups 136.4 8.525
Total 348.8
a) What is the within groups degrees of freedom for this analysis? Explain how you obtain your answer.
b) What is the total degrees of freedom? Explain how you obtain your answer.
c) What is the among-group (between-group) mean squares? Explain how you obtain your answer.
d) At a significance level of 1%, what conclusion can you infer? Explain how you obtain your answer.
Mathematics
1 answer:
zzz [600]3 years ago
4 0

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Oksana_A [137]
Were there choices?

The next step is to add inside the parenthesis
18+23=41
8 0
2 years ago
The spokes of a bicycle wheel form 10 congruent central angles. The diameter of the circle formed by the outer edge of the wheel
N76 [4]

find the circumference and divide it by 10

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4 0
3 years ago
Solve. 3 + x > -9 A) x > 3 B) x > -6 C) x > -3 D) x > -12
IRISSAK [1]

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2 years ago
Wrire a fraction that is less than 5/6 and has a denominator of 8
gulaghasi [49]
...0/8, 1/8, 2/8, 3/8, 4/8, 5/8
3 0
2 years ago
In the diagram,
forsale [732]

Answer:

Probability that the measure of a segment is greater than 3 = 0.6

Step-by-step explanation:

From the given attachment,

AB ≅ BC, AC ≅ CD and AD = 12

Therefore, AC ≅ CD = \frac{1}{2}(\text{AD})

                                  = 6 units

Since AC ≅ CD

AB + BC ≅ CD

2(AB) = 6

AB = 3 units

Now we have measurements of the segments as,

AB = BC = 3 units

AC = CD = 6 units

AD = 12 units

Total number of segments = 5

Length of segments more than 3 = 3

Probability to pick a segment measuring greater than 3,

= \frac{\text{Total number of segments measuring greater than 3}}{Total number of segments}

= \frac{3}{5}

= 0.6

4 0
3 years ago
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