Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.
<h3>How far did the outfielder throw the ball?</h3>
Based on the shape of a mound, the law of cosines can be used.
The distance the ball was thrown by the outfielder can therefore be d.
Distance is:
d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))
d ²= 33,484.42ft
Then find the square root:
d = √33,484.42
= 182.9874
= 183 ft
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Answer:
37.68 ft^3
Step-by-step explanation:
The parameters used in describing a cone is radius and height
Hence
Radius= 3ft
Height = 2 ft
The volume of a cone is given as
substitute
Hence the volume is 37.68 ft^3
Answer:
yes, because they have the same angle measures.
(congruent triangles have equal angles)
Step-by-step explanation:
Answer:
x = 9
y = 15
Step-by-step explanation:
x = 9
y = 15
I'm not sure how to explain this, but one side is equal to its opposite side in a parallelogram.
Hope this helps :)
Answer:
5/2
Step-by-step explanation:
