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finlep [7]
3 years ago
13

The vertex of this parabola at (-5,-2). When the c - value is -4 the y-value is 2 what is the coefficient of the squared express

ion in the parabolas equation. ( to answer gets brainliest )

Mathematics
1 answer:
Andre45 [30]3 years ago
3 0

Answer:

4

Step-by-step explanation:

The vertex formula of a quadratic equation is:

●y= a(x-h)^2 +k

(h,k) are the coordinates of the vertex

Here: h = -5 and k= -2

y is 2 and x is -4

● 2 = a (-4-(-5))^2 + (-2)

● 2 = a (-4+5)^2 -2

● 2 = a *1^2 -2

● 2 = a -2

● 4 = a

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A table and 8 chairs weigh 234.68 lb together. If the table weighs 157.84 lb, what is the weight of one chair in pounds?
Trava [24]
You subtract 234.68 and 157.84 and you get 76.84lb
5 0
3 years ago
Two similar cylinders have radii of 15 inches and 6 inches. What is the ratio of the surface area of the small cylinder to the s
Levart [38]

Answer:

4:25

Step-by-step explanation:

Given that,

r₁ = 15 inches, r₂ = 6 inches

The area of the cylinder is given by :

A=2\pi rh+2\pi r^2

The ratio of surface areas of two cylinders,

\dfrac{S_2}{S_1}=\dfrac{2\pi r_2h_2+2\pi r_2^2}{2\pi r_1h_1+2\pi r_1^2}\\\\\dfrac{S_2}{S_1}=(\dfrac{r_2}{r_1})^2\\\\=\dfrac{6}{15}^2\\\\=\dfrac{4}{25}

Hence, the required ratio is 4:25.

8 0
3 years ago
Write three ways to find different bases for 64
bixtya [17]
8^2, 4^3, and 2^6 are 3 ways
4 0
3 years ago
WILL GIBE BRAINLIEST ASAP
Romashka [77]

Answer:

A and D have whole grid squares that are the same size and aren't over lapping

C has overlapping grid squares making it hard to count

B can't be used to find area because some of the grid squares are different sizes

You still could use B because four of the smaller squares seems to be equivalent to one of the larger squares

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The total cost of painting of four walls of a square hall at Rs. 40 per sq. m. is Rs. 12000. If the hall contains 600 m³ of air,
astra-53 [7]

Answer:

The height of the hall is 9.375 meters

Step-by-step explanation:

The rate at which the walls of the square hall are painted, R = Rs. 40 per sq. m.

The total cost of painting the square hall, C = Rs. 12,000

The volume of air contained in the hall, V = 600 m³

The surface area of the four walls of the hall, A = C/A

∴ A = Rs. 12,000/(Rs. 40/m²) = 300 m²

Let 's' represent the length of sides of the square hall, and let 'h' represent the height of the square wall, we have;

The volume of the hall, V = s² × h

The surface area of the wall, A = 4 × s × h

Therefore, we get;

A = 300 = 4 × s × h

V = 600 = s² × h

V/A = 600/300 = 2 = s² × h/(4 × s × h) = s/4

s/4 = 2

s = 4 × 2 = 8

The side length of the square hall, s = 8 m.

From the area, A = 4 × s × h, we get;

A = 300 = 4 × 8 × h

h = 300/(4 × 8) = 9.375

The height of the hall, h = 9.375 m.

8 0
3 years ago
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