Correct, c and e. they are the only ones that make sense
Here you have black dots at x = {0, 1, 2, 4, 4.5, 5}.
For each of these x-values, there is one and only one associated y-value. This fact tells us that the graph does represent a function.
Given:
The scale factor is 1:12.
Dimension of model = 32 cm
To find:
The actual dimension in m.
Solution:
Let x be the actual dimension.
The scale factor is 1:12 and the dimension of model is 32 cm.

On cross multiplication, we get


![[\because 1\ m=100\ cm]](https://tex.z-dn.net/?f=%5B%5Cbecause%201%5C%20m%3D100%5C%20cm%5D)
Therefore, the actual dimension is 3.84 m.
Since the outside is 1.5 to 1, we take half of the value of the inside diameter and add it to itself to get the smallest value needed. 0.5+0.25=0.75
So the smallest diameter possible would be 0.75 inches.
M+p=475
m=p-61
replace m in equation 1 with p-61: p-61+p=475
2p=475+61=536
p=268
m=207