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Anon25 [30]
3 years ago
13

If it’s too blurry let me know. I’ve been plugging in these points and idk maybe I’m doing something wrong but o can’t get the l

eft to equal 1.

Mathematics
1 answer:
nika2105 [10]3 years ago
4 0

Answer: A. -4

Step-by-step explanation:

6/((-4)^2-9)-(1/-4-3)= 6/7+1/7=1

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What is the equation of the line that passes through the point (-6, -8) and has a slope of 1/3
ivanzaharov [21]

Answer <u>(assuming it can be in point-slope form)</u>:

y + 8 = \frac{1}{3} (x+6)

Step-by-step explanation:

With the given information, we can use the point-slope formula, y-y_1 = m (x-x_1), to write the equation of the line. Substitute values for the m , x_1, and y_1 in the formula to do so.

The m represents the slope, so substitute \frac{1}{3} in its place. The x_1 and y_1 represent the x and y values of one point the line intersects, so substitute -6 for x_1 and -8 for y_1. This gives the following answer and equation (just make sure to convert the double negatives into positives:  

y-(-8) = \frac{1}{3} (x-(-6))\\y + 8 = \frac{1}{3} (x+6)

3 0
3 years ago
Read 2 more answers
2.4 ×10 to the 6 +3.4 ×10 to the 3
kati45 [8]
Idk i’m sorry but try your best and u will succeed
4 0
3 years ago
32 = 1.69 is this correct
ddd [48]
Yes this is correct answer
3 0
3 years ago
Which are the solutions of the quadratic equation x^2=-5x-3
frutty [35]
The correct answer would be \frac{-5 +/-  \sqrt{13} }{2}

In order to solve for this you must first get the equation equal to 0. 

<span>x^2=-5x-3 ----> add 5x to both sides. 
x^2 + 5x = -3 ----> add 3 to both sides.
x^2 + 5x + 3 = 0

Now knowing this we can use the coefficients of each one in descending order of power as a, b and c. 

a = 1 (because it is the coefficient to x^2)
b = 5</span> (because it is the coefficient to x)
c = 3 (because it is the end number)

Now we can plug these values into the quadratic equation. 

\frac{-b +/-  \sqrt{b^{2} - 4ac } }{2a}

\frac{-5 +/- \sqrt{5^{2} - 4(3)(1) } }{2(1)}

\frac{-5 +/- \sqrt{13} }{2}

And those would be your two answers.
5 0
3 years ago
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tankabanditka [31]
Help what ??? I don’t see anything
6 0
3 years ago
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