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musickatia [10]
2 years ago
6

Need B and C PLEASE HELP

Mathematics
1 answer:
daser333 [38]2 years ago
6 0

Answer:

B

Step-by-step explanation:

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G(a) = 4a<br>ha)=a² + 2a<br>Find (g - h)(a)​
Reil [10]

Step-by-step explanation:

all work is shown and pictured

4 0
3 years ago
Choose the equation that matches the following situation: For a field trip, 24 students rode in cars and the rest filled three b
olchik [2.2K]

Answer:

96 = 24 + 3b

96 students in all, 24 in cars and the rest in 3 buses

8 0
3 years ago
Find Horizontal and Vertical asymptotes for y=(x^2 -9)/(4x^2 +1)
Gnom [1K]

Answer: Horizontal asymptote is \dfrac{1}{4} and vertical asymptotes are \pm \dfrac{1}{2i}

Step-by-step explanation:

Since we have given that

y=\dfrac{x^2-9}{4x^2+1}

We need to find the horizontal and vertical asymptotes.

Since vertical asymptotes will occur where the denominator becomes zero.

So, here denominator is 4x^2+1

Now,

4x^2+1=0\\\\4x^2=-1\\\\x^2=\dfrac{-1}{4}\\\\x=\pm \dfrac{1}{2i}

And the horizontal asympototes will occur when the coefficient of higher degree of numerator is divided by coefficient of higher degree of denominator.

y=\dfrac{1}{4}

Hence, horizontal asymptote is \dfrac{1}{4} and vertical asymptotes are \pm \dfrac{1}{2i}

8 0
3 years ago
T is the midpoint of RS, T has coordinates (6, 4), and S has coordinates (3,-2). What are the
Fynjy0 [20]

Answer:

help

Step-by-step explanation:

3 0
3 years ago
Please help!!!!! pls pls pls asap
kow [346]

Answer: 78

Step-by-step explanation:

First, we want to find the area of the outer triangles. Remember that the equation to finding the area of a triangle is (l x h) x 1/2. So, let’s substitute the values into the equation. It’ll be (6 x 7) x 1/2. Let’s solve! 6 x 7 = 42. Then, 42 x 1/2 = 21. But let’s not forget that we only found the area of one triangle. We still need to find the area of the other outer triangles. So, to do this, we take 21 and multiply by 3 since the other outer triangles have the same dimensions. We would get 63 as our total area for the outer triangles.

Next, we need to find the area for the inner triangle. We will use the same equation: (l x h) x 1/2. Let’s substitute! (6 x 5) x 1/2 will be our final equation. Now, let’s solve. 6 x 5 = 30. 30 x 1/2 = 15. So, as a process of elimination, our area for the inner triangle is 15.

Finally, we need to add the total areas we found together. Our total areas were 63 and 15. Let’s put this into an equation: 63 + 15 = ?. So, 63 + 15 = 78. So, after a long process, 15 is our answer!

Hope this helped!

6 0
3 years ago
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