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Dimas [21]
3 years ago
10

Assume that in squashes the difference in fruit weight between a 3-lb type and a 6-lb type results from three independently segr

egating allele pairs, A/a, B/b, and C/c. Each capital-letter allele contributes a half-pound to the weight of the squash. From a cross of a 3-lb plant (aa bb cc) with a 6-lb plant (AA BB CC), what will be the phenotypes (weights) of the F1 AND F2? What will be their distribution?
Biology
1 answer:
3241004551 [841]3 years ago
8 0

Answer:

F1: Aa Bb Cc: 4.5 lbs

F2: Too many to list: Between 3 lbs and 6 lbs

Explanation:

F1: Aa Bb Cc, will be the genotypes and will weigh 4.5 lbs, the reason for that is because each capital letter allele adds half a pound to the base weight of 3 lbs.

F2: There are many different genotypes that can be present in the second generation, for example (AA BB CC, AA BB Cc, AA BB cc, etc.) each of which will allow the plant to grow to a certain height. The majority of phenotypes will be 4.5 lbs. There will be one who is AA BB CC, and another one person who has the code, aa bb cc.

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Put the steps of DNA Replication in the correct order.
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Answer:

1. The 2 bases forming each rung of the 'ladder' snap apart. This is caused by an enzyme that passes along the strands, 'unzipping' it

2. Spare nucleotides (in the nucleus of the cell) attach themselves to the 'broken rungs' to repair the break. Each repairing nucleotide is identical to the broken one

3. As each 'broken rung' is repaired, two 'ladders' form, that is 2 identical strands of DNA. The 'repairing' is really the process of replica

Explanation:

Hope this helps!

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3 years ago
Observing the temporal bone and locates the jugular foramen and the jugular fossa. what two types of bone markings has she ident
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3 years ago
Suppose that at a given point along a capillary, the following forces exist: Capillary hydrostatic pressure (HPc) = 30 mmHg Inte
Ainat [17]

Answer:

Suppose that at a given point along a capillary, the following forces exist: Capillary hydrostatic pressure (HPc) = 30 mmHg Interstitial fluid hydrostatic pressure (HPif) = 0 mmHg Capillary colloid osmotic pressure (OPc) = 25 mmHg Interstitial fluid colloid osmotic pressure (OPif) = 2 mmHg. The net filtration pressure at this point in the capillary is <u>7mmHg.</u>

Explanation:

  • Data:

Capillary hydrostatic pressure (HPc) = 30 mmHg

Interstitial fluid hydrostatic pressure (HPif) = 0 mmHg

Capillary colloid osmotic pressure (OPc) = 25 mmHg

Interstitial fluid colloid osmotic pressure (OPif) = 2 mmHg

  • Formula Applied :

Net filtration pressure= hydrostatic pressure gradient -  Oncotic pressure gradient

Hydrostatic pressure gradient = Capillary hydrostatic pressure - Interstitial hydrostatic pressure = 30mmHg - 0 mmHg = 30 mmHg

Oncotic pressure gradient =  Capillary colloid osmotic pressure - Interstitial fluid colloid osmotic pressure =25  - 2 = 23 mmHg

Net filtration pressure= hydrostatic pressure gradient -  Oncotic pressure gradient = 30 mmHg - 23 mmHg = 7 mmHg.

Hence, The net filtration pressure at this point in the capillary is <u>7mmHg.</u>

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<u />

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