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Alisiya [41]
4 years ago
12

Identify the domain and the range of the relation.

Mathematics
1 answer:
zmey [24]4 years ago
6 0
C i think Idk for sure












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What is the value of q
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70

Step-by-step explanation:

angles on a straight line add up to 180 degrees add 52+58=100 then minus from 180 =70

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if the rectangle below is enlarged using a scale factor of 2.5, what will be the perimeter and area of the new rectangle?
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A spyware is trying to break into a system by guessing its password. It does not give up until it tries 1 million different pass
Juliette [100K]

Answer: So our limit is 1 million attempts.

a) 6 lower case letters.

Think in 6 blank spaces where you can put one letter, so in each space you have 26 options, so the total of combinations is 26^{6} = 308915776.

so if you have 1 million attempts, then 1000000/308915776 = 0.00323

so you have 0.32% chances of breaking the code.

b) 6 different letters, some may be upper-case, and it is case-sensitive

Again 6 blank spaces, in the first you can put 26 letters,  and because its case sensitive, you have 52 options, in the second space, you will have 25 posible letters, and 50 options, and so on.

So the total combinations are 52*50*48*46*44*42 = 10608998400

and the probability of breaking it with 1 mill attempts is = 0.009%

(c) any 6 letters, upper- or lower-case, and it is case-sensitive

same as the first case, but here you have 26 lower case and 26 upper, so you have 52^{6} = 19770609664 combinations

and in 1 mill attempts the probability of breaking it is 0.0005%

(d) any 6 characters including letters and digits

Here you have 26 letters and 10 numbers, so the total combinations are :

36^{6} = 2176782336

and the probability of breaking it will be 0.004%

were in all cases you must think that each attempt made by the spyware is a different combination, so the one million tries are different combinations.

7 0
3 years ago
1) Is QSRE RTQ ? Give reasons.
PSYCHO15rus [73]

Answer:

(i) In triangle RTO and QSR

Given,

⇒∠RTO=∠OSR=90

o

(QS⊥PR and RT⊥PQ)

⇒QS=RT

⇒QR=RO ....Hypotenuse

∴△RTQ≅△QSR ....RHS criterion

(ii) By using part(1) of a solution, we get

∠TQR=∠SRQ ....By C.P.C.T

⇒∠PQR=∠PRQ

Step-by-step explanation:

hope \: it \: helps \: you

4 0
3 years ago
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