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Natalija [7]
3 years ago
6

Triangle L M Q is cut by perpendicular bisector L N. Angle N L Q is 32 degrees and angle L M N is 58 degrees. Is TriangleMNL ≅ T

riangleQNL? Why or why not? A: Yes, they are congruent by either ASA or AAS.
B: Yes, they are both right triangles.
C: No, AngleM is not congruent to AngleNLQ.
D: No, there are no congruent sides.
Mathematics
2 answers:
mariarad [96]3 years ago
7 0

Answer:

A Yes, they are congruent by either ASA or AAS.

Step-by-step explanation:

lorasvet [3.4K]3 years ago
6 0

Answer:

A

Step-by-step explanation:

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lidiya [134]

Answer:

f(-2) = 0

f(1) = 12

f(2) = 5

Step-by-step explanation:

f(-2) will lie in the function f(x) =x^2 - 4

\therefore f( - 2) =  {( - 2)}^{2}  - 4 = 4 - 4 = 0

f(1) will lie in the function f(x) =2x^2 +10

\therefore f(1) = 2 {(1)}^{2}  + 10 = 2 + 10 = 12

f(2) will lie in the function f(x) =5

\therefore f(2) = 5

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3 years ago
In the given figure, BAC = 90° and ABC = 45°. Prove that: AB = AC. ​
Amiraneli [1.4K]

Answer:

<h2>By angle sum property:</h2>

BAC+ABC+BCA=180°

90°+45°+x=180°

135°+x=180°

x=45°=BCA

<h2>since BCA=ABC=<u> </u>45° each </h2><h2>therefore,</h2>

AB=AC \\ (isosceles \: triangle \:  \\ theorem)

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A circular pond 20m in diameter is surrounded by a gravel path 5m wide. The path is to be replaced by a brick walk costing $30 p
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3 years ago
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An adult ticket to a museum costs 3$ more than a children’s ticket. When 200 adult tickets and 100 children tickets are sold, th
antiseptic1488 [7]

The cost of children’s ticket is $ 5

<h3><u>Solution:</u></h3>

Let "c" be the cost of one children ticket

Let "a" be the cost of one adult ticket

Given that adult ticket to a museum costs 3$ more than a children’s ticket

<em>Cost of one adult ticket = 3 + cost of one children ticket</em>

a = 3 + c  ------ eqn 1

<em><u>Given that 200 adult tickets and 100 children tickets are sold, the total revenue is $2100</u></em>

200 adult tickets x cost of one adult ticket + 100 children tickets x cost of one children ticket = 2100

200 \times a + 100 \times c = 2100

200a + 100c = 2100 ------ eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>

Substitute eqn 1 in eqn 2

200(3 + c) + 100c = 2100

600 + 200c + 100c = 2100

600 + 300c = 2100

300c = 1500

<h3>c = 5</h3>

Thus the cost of children’s ticket is $ 5

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