What two decimals have a sum of 8.6

Soloha48 [4]

Answer:

Both of the equations are right because if you take s=4p, then reverse it, p=1/4 of s because 4 of p is equal to s so s/4 = p

6 0

2 years ago

Find the sum that amounts to Rs 9,144 in 3 years at 9% per year simple interest.

Hunter-Best [27]

Given:

Amount = Rs. 9,144

Time = 3 years.

Rate of simple interest = 9%

To find:

The principal value.

Solution:

The formula for simple interest is:

$I=\dfrac{P\times r\times t}{100}$

Where, P is principal, r is the simple rate of interest, and t is the number of years.

Putting $r=9,t=3$ in the above formula, we get

$I=\dfrac{P\times 9\times 3}{100}$

$I=\dfrac{27P}{100}$

$I=0.27P$

We know that,

$\text{Amount}=\text{Principal + Interest}$

$9144=P+0.27P$

$9144=1.27P$

Divide both sides by 1.27, we get

$\dfrac{9144}{1.27}=P$

$7200=P$

Therefore, the principal value is Rs. 7200.

8 0

3 years ago

Find the measures of the angles of a triangle if the measure of one angle is twice the measure of a second angle and the third a

guapka [62]

Answer:

Step-by-step explanation:

A triangle consists of 3 angles and sides. The sum of the angles in a triangle is 180°. Let the angle be <A, <B and <C.

<A + <B + <C = 180° ...... 1

If the measure of one angle is twice the measure of a second angle then

<A = 2<B ...... 2

Also if the third angle measures 3 times the second angle decreased by 48, this is expressed as <C = 3<B-48............ 3

Substituting equations 2 and 3 into 1 will give;

(2<B) + <B + (3<B-48) = 180°

6<B- 48 = 180°

add 48 to both sides

6<B-48+48 = 180+48

6<B = 228

<B = 228/6

<B =38°

To get the other angles of the triangle;

Since <A = 2<B from equation 2;

<A = 2(38)

<A = 76°

Also <C = 3<B-48 from equation 3;

<C = 3(38)-48

<C = 114-48

<C = 66°

<em>Hence the measures of the angles of the triangle are 38°, 66° and 76°</em>

4 0

3 years ago

Hans deposits $300 into an account that pays simple interest at a rate of 2% per year. How much interest will he be paid in the

blagie [28]

300 x 0.02 x 5 = 30
answer
<span> interest will $30 in the first 5 years</span>

5 0

3 years ago

A spring exerts a force of 6 N when stretched 3 m beyond its natural length. How much work is required to stretch the spring 2 m

lys-0071 [83]

Answer:

4Joules

Step-by-step explanation:

According to Hooke's law which states that extension of an elastic material is directly proportional to the applied force provide that the elastic limit is not exceeded. Mathematically,

F = ke where

F is the applied force

K is the elastic constant

e is the extension

If a spring exerts a force of 6 N when stretched 3 m beyond its natural length, its elastic constant 'k'

can be gotten using k = f/e where

F = 6N, e = 3m

K = 6N/3m

K = 2N/m

Work done on an elastic string is calculated using 1/2ke².

If the spring is stretched 2 m beyond its natural length, the work done on the spring will be;

1/2× 2× (2)²

= 4Joules

3 0

3 years ago