The function f(x) = 2|x – 2| + 6 has a vertex at (2, 6) option second is correct.
<h3>What is a function?</h3>
It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
We have a function that has vertex at (2, 6)
The options are:
f(x) = 2|x – 2| – 6
f(x) = 2|x – 2| + 6
f(x) = 2|x + 2| + 6
f(x) = 2|x + 2| – 6
As we know the vertex form of a quadratic function is given by:
f(x) = a(x - h)² + k
Similarly, mod function can be expressed as:
m(x) = a|x - h| + k
Here (h, k) is the vertex of a function.
In the function:
f(x) = 2|x – 2| + 6
The vertex of the function is (2, 6)
Thus, the function f(x) = 2|x – 2| + 6 has a vertex at (2, 6) option second is correct.
Learn more about the function here:
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Answer:
-14
Step-by-step explanation:
2c + d
We are given the values of c and d:
c = -9
d = 4
We substitute in these values
2(-9) + 4 = ?
2 times -9 is -18
-18 + 4 = -14
2c + d = -14
Answer:
1) 760
2)1970
3) 1110
Step-by-step explanation:
Would use the algorithm for solving square root.
For square root, √n
x₁ = 0.5(x₀ + n/x₀)
(This formula is known and for square root, and can be derived using Newton-Raphson's approximation equation)
Where x₀ is the initial guess. x₁ becomes the new guess.
For √100.6 let our initial guess be 10, x₀ = 10, n = 100.6
Our approximation shall be to 3 decimal places. Once we get the same answer twice we stop the algorithm.
x₀ = 10, x₁ = 0.5(x₀ + n/x₀), x₁ = 0.5(10 + 100.6/10) = 10.030, x₁ = 10.030
x₂ = 0.5(x₁ + n/x₁), x = 0.5(10.030 + 100.6/10.030) ≈10.015, x₂ ≈ 10.030 (to 3 decimal places)
Since x₂≈ x₁, the algorithm stops.
So the √100.6 is ≈ 10.030 to 3 decimal places.
I hope this helps.
Well the answer is x^2 - 16x + 63
