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laiz [17]
2 years ago
14

The ratio of boys to girls in a class is 4:5

Mathematics
2 answers:
mestny [16]2 years ago
6 0

Answer:

4/9 5/9

Step-by-step explanation:

Dimas [21]2 years ago
5 0

Answer:

Boys = 4/9

Girls = 5/9

Step-by-step explanation:

You add the ratio parts to find what the fraction is over.

5 + 4 = 9

Then you just need to know which part is boys and which is girls.

Boys to Girls = 4:5

Therefore Boys = 4/9 and Girls = 5/9.

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Match each equation with its solution set. Tiles a2 − 9a + 14 = 0 a2 + 9a + 14 = 0 a2 + 3a − 10 = 0 a2 + 5a − 14 = 0 a2 − 5a − 1
sattari [20]
We have that

N 1)
a²<span> − 9a + 14 = 0 
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² − 9a)=-14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² − 9a+20.25)=-14+20.25

Rewrite as perfect squares

(a-4.5)²=6.25--------> (a-4.5)=(+/-)√6.25

a1=4.5+√6.25-----> a1=7

a2=4.5-√6.25-----> a2=2

the solution problem N 1 is the pair {7, 2}


N 2) 

a²<span> + 9a + 14 = 0
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 9a)=-14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² +9a+20.25)=-14+20.25

Rewrite as perfect squares

(a+4.5)²=6.25--------> (a+4.5)=(+/-)√6.25

a1=-4.5+√6.25-----> a1=-2

a2=-4.5-√6.25-----> a2=-7

the solution problem N 2 is the pair {-2,-7}

N 3) 

a² + 3a − 10 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 3a)=10

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² + 3a+2.25)=10+2.25

Rewrite as perfect squares

(a+1.5)²=12.25------> (a+1.5)=(+/-)√12.25

a1=-1.5+√12.25-----> a1=2

a2=-1.5-√12.25-----> a2=-5

the solution problem N 3 is the pair {2, -5}


N 4)

a²<span> + 5a − 14 = 0
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 5a) =14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² + 5a+6.25) =14+6.25

Rewrite as perfect squares

(a+2.5)² =20.25-------> (a+2.5)=(+/-)√20.25

a1=-2.5+√20.25-----> a1=2

a2=-2.5-√20.25-----> a2=-7

the solution problem N 4 is the pair {2, -7}


N 5) 

a² − 5a − 14 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² − 5a)=14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² − 5a+6.25)=14+6.25

Rewrite as perfect squares

(a-2.5)²=2025--------> (a-2.5)=(+/-)√20.25

a1=2.5+√20.25-----> a1=7

a2=2.5-√20.25-----> a2=-2

the solution problem N 5 is the pair {7, -2}

3 0
3 years ago
Read 2 more answers
What's the answer for 4a - 13=19
pashok25 [27]
4a-13=19  add 13 to both sides
4a=32     divide by 4 on both sides
a=8

5 0
3 years ago
Which describes the solution of the inequality y &gt; −15? Select all the points that are part of the solution.
Svetllana [295]

Step-by-step explanation:

y > -15

y is bigger than -15

= -14 , -13 , -12 , -11 , -10 , etc . . .

8 0
3 years ago
Which expression is equivalent to<br> Square root of 80 ?
Lana71 [14]

Answer:

4i√5

Step-by-step explanation:

3 0
3 years ago
Running at an average rate of 4 meters per second, a sprinter ran to the end of a track. The sprinter then jogged back to the st
yaroslaw [1]
<h2>Length of track is 168 meter</h2>

Step-by-step explanation:

Let l be the length of track.

Running speed = 4 m/s

Jogging speed = 2 m/s

Total time taken = 2 minutes 6 seconds. = 126 seconds

That is

            \frac{l}{4}+\frac{l}{2}=126\\\\0.75l=126\\\\l=168m

Length of track is 168 meter

5 0
3 years ago
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