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Rus_ich [418]
3 years ago
5

The load that can be supported by a rectangular beam varies jointly as the width of the beam and the square of itsâ height, and

inversely as the length of the beam. A beam feetâ long, with a width of inches and a height of inches can support a maximum load of pounds. If a similar board has a width of inches and a height of âinches, how long must it be to support âpounds?
Mathematics
1 answer:
storchak [24]3 years ago
6 0

The question is incomplete.Here is the complete question.

The load that can be supported by a rectangular beam varies jointly as the width of the beam and the square of its length, and inversely as the length of the beam. A beam 13 feet long, with a width of 6 inches and a height of 4 inches can support a maximum load of 800 pounds. If a similar board has a width of 8 inches and a height of 7 inches, how long must it be to support 1300 pounds?

Answer: It must be 392 inches or approximately 33 feet.

Step-by-step explanation: According to the question, the measures (width, length and height) of a beam and the weight it supports are in a relation of <u>proportionality</u>, i.e., if divided, the result is a constant.

For the first load:

width = 6in

height = 4in

length = 13ft or 156in

weight = 800lbs

Then, constant will be:

\frac{6.4^{2}}{156} k = 800

k=\frac{800.156}{96}

k = 1300

For the similar beam:

\frac{8.7^{2}}{L}1300=1300

L = 49.8

L = 392in or 32.8ft

A similar board will support 1300lbs if it has 392 inches or 32.8 feet long.

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United Blood Services is a blood bank that serves more than 500 hospitals in 18 states. According to their website, a person wit
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Answer:

a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.

b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.

Step-by-step explanation:

I am going to solve this question treating these events as Venn probabilities.

I am going to say that:

Event A: Person has type A blood.

Event B: Person has Rh- factor.

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This means that P(A) = 0.43

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This means that P(B) = 0.15

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This means that P(A \cup B) = 0.52

a. Find the probability that a person has both type O blood and the Rh- factor.

This is

P(A \cap B) = P(A) + P(B) - P(A \cup B)

With what we have

P(A \cap B) = 0.43 + 0.15 - 0.52 = 0.06

0.06 = 6% probability that a person has both type O blood and the Rh- factor.

b. Find the probability that a person does NOT have both type O blood and the Rh- factor.

1 - 0.06 = 0.94

0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.

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