Step 1: Assign variable for the unknown that you need to find.

Step 2: List the given details
Distance between you and your friend is 12 miles. It means the total distance traveled by you by walk and your friend using bicycle when both travel towards each other to meet in 't' hours
Equation 1:

Your Walking rate and your friends Cycling rate is given below:

Step 3: Set up an equation using the relationship between distance, time and rate.


Substituting the above in equation 1

Distance traveled by you by walking from home and distance travelled by your friend in cycle in 0.8 hours is given below:

Answer:
a.
Step-by-step explanation:
Each system has a different purpose. one for the cost, and one for the pounds.
x+y=12 is for the pounds
since each pound of dried fruit cost $6 and each pound of nuts cost $2, and you can only spend $40,
6x+2y=40
Answer:
1. The car is slowing down at a rate of 2.5mph/s
2. The greatest acceleration is 10 mph/s.
3. In the interval 4s to 16s the speed remains constant and has magnitude 25 mph.
Step-by-step explanation:
1. The deceleration of the car is from 16 seconds to 24 seconds is the slope
of the graph from 16 to 24:

the negative sign indicates that it is deceleration.
2. The automobile experiences the greatest change in speed when the slope is greatest because that is when acceleration/deceleration is greatest.
From the graph we see that the greatest slope of the graph is between 28 and 24 seconds. The acceleration the interval is the slope
:

3. The automobile experiences no acceleration in the interval 4 s to 16 s—that's the graph is flat.
The speed of the automobile in that interval, as we see from the graph, is 25 mph.
Answer:
x = 3, -5
Step-by-step explanation:
hope this helps plz give brainiest