I'd like to see some of your own efforts here. This is the third time you've posted two "factor completelyl" problems, without sharing what you've already done.
<span>3v^2 - 8v - 16 cannot be reduced. Thus, your best choice to find roots is to apply the quadratic formula:
8 plus or minus sqrt( 64-4(3)(-16) )
v = ---------------------------------------------------
2(3)
8 plus or minus sqrt( 64 + 192 )
= ---------------------------------------------
6
8 plus or minus sqrt(256)
= -------------------------------------
6
= 8 + 16, all divided by 6, or 8 - 16, all divided by 6
= 4 or -8/6, or 4 or -4/3.
The factors are (v-4) and (v + 4/3).</span>
Answer:
B
Step-by-step explanation:
Soo sorry if i am worng :(
16x^4-81y^4 difference of perfect squares...
(4x^2-9y^2)(4x^2+9y^2) that's one of the equivalents...
(2x+3y)(2x-3y)(4x^2+9y^2) that's another one of them...
The answer is D because if the perimeter of wxyz can be found by multiplying 2 with the perimeter of hjkl, then the area would be area of hjkl times 2
Answer:
6
Step-by-step explanation:
The order of the polynomial is 6 (look at the highest exponent). So there are 6 roots.
