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3 years ago

Given h(x) = 4x – 5, solve for a when h(x) = 7.

Mathematics

2 answers:

spayn [35]3 years ago

4 0

Answer:

Step-by-step explanation:

h(7)= 4(7) - 5

h(7)= 28 - 5

h(7)= 23

Elenna [48]3 years ago

3 0

h(x)=4x-5

$\\ \sf\longmapsto h(7)$

$\\ \sf\longmapsto 4(7)-5$

$\\ \sf\longmapsto 28-5$

$\\ \sf\longmapsto 23$

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Help please! math volumes

salantis [7]

Answer:

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Step-by-step explanation:

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1 year ago

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3 years ago

Read 2 more answers

PLASE ANSWER THIS QUESTION I GIVE YOU 18 POINTS

sukhopar [10]

Answer:

(a) 144

(b) 117

(d) 588

(e) 5472

Step-by-step explanation:

To find the LCM of two numbers, first find the prime factorization of each number. Then the LCM is the product of common and not common factors with the larger exponent.

(a)

$72 = 2^3 \times 3^2$

$144 = 2^4 \times 3^2$

$LCM = 2^4 \times 3^2 = 8 \times 9 = 144$

(b)

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$117 = 3^2 \times 13$

$LCM = 3^2 \times 13 = 117$

(c)

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$LCM = 2^3 \times 3^2 \times 5 = 360$

(d)

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$147 = 3 \times 7^2$

$LCM = 2^2 \times 3 \times 7^2 = 588$

(e)

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2 years ago

72 greater than a is at least 7

KonstantinChe [14]

It could be? the 7 could be 7 to literally any number soooo

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3 years ago

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kvv77 [185]

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3 years ago