Area=1/2 times base times height
note:bh=base times height
a=1/2bh
b=width
h=-4+2w
h=2w-4
subsitute
a=1/2w(2w-4)
a=1/2(2s^2-4w)
a=w^2-2w
a=63
63=w^2-2w
subtract 63 from both sdies
0=w^2-2w-63
factor
find what 2 numbers multiply to get -63 and add to get -2
the numbers are -9 and 7
so
0=(w-9)(w+7)
if xy=0 then x and/or y=0
so
w-9=0
w+7=0
solve each
w-9=0
add 9 to both sdies
w=9
w+7=0
subtract 7 from both sides
w=-7
width cannot be negative so this can be discarded
width=9
subsitute
l=2w-4
l=2(9)-4
l=18-4
l=14
legnth=14 in
width/base=9 in
Let the lesser number be x and y the greater. Then
x + 65 = 4y , Also
y - x = 2
Adding:-
y + 65 = 4y + 2
63 = 3y
y = 21
and
x = 21-2 = 19
Answer the 2 odd numbers are 19 and 21.
Answer:
A
Step-by-step explanation:
for a right angled triangle, the sum of the square of the two sides should be equal to the square of the hypotenuse. If this rule does not hold, the dimensions do not represent the side of a right angled triangle.
The Pythagoras theorem : a² + b² = c²
where a = length
b = base
c = hypotenuse
4² + 10² ≠ 16²
6² + 12² = 13²
7² + 24² = 25²
8² + 15² = 17²
Answer:
x / 3 = -8
Step-by-step explanation:
Answer:
Step-by-step explanation:
Subtract 7 From both sides
7-7 = 0, 16 - 7=9
That leaves 
Hope this helps
~R3V0
