Answer:
x=9 and y=3
Step-by-step explanation:
Let's solve your system by substitution.
−4x+6y=−18 and y=−2x+21
Rewrite equations:
y=−2x+21;−4x+6y=−18
Step: Solve y=−2x+21for y:
y=−2x+21
Step: Substitute−2x+21foryin−4x+6y=−18:
−4x+6y=−18
−4x+6(−2x+21)=−18
−16x+126=−18(Simplify both sides of the equation)
−16x+126+−126=−18+−126(Add -126 to both sides)
−16x=−144
−16x
−16
=
−144
−16
(Divide both sides by -16)
x=9
Step: Substitute9forxiny=−2x+21:
y=−2x+21
y=(−2)(9)+21
y=3(Simplify both sides of the equation)
Answer:
x=9 and y=3
Let p(x) be a polynomial, and suppose that a is any real
number. Prove that
lim x→a p(x) = p(a) .
Solution. Notice that
2(−1)4 − 3(−1)3 − 4(−1)2 − (−1) − 1 = 1 .
So x − (−1) must divide 2x^4 − 3x^3 − 4x^2 − x − 2. Do polynomial
long division to get 2x^4 − 3x^3 − 4x^2 – x – 2 / (x − (−1)) = 2x^3 − 5x^2 + x –
2.
Let ε > 0. Set δ = min{ ε/40 , 1}. Let x be a real number
such that 0 < |x−(−1)| < δ. Then |x + 1| < ε/40 . Also, |x + 1| <
1, so −2 < x < 0. In particular |x| < 2. So
|2x^3 − 5x^2 + x − 2| ≤ |2x^3 | + | − 5x^2 | + |x| + | − 2|
= 2|x|^3 + 5|x|^2 + |x| + 2
< 2(2)^3 + 5(2)^2 + (2) + 2
= 40
Thus, |2x^4 − 3x^3 − 4x^2 − x − 2| = |x + 1| · |2x^3 − 5x^2
+ x − 2| < ε/40 · 40 = ε.
Positive if it is an increase.
Does that help? Idrk what ur asking
Answer:
Step-by-step explanation:
5,520 will be added because 6000-8% is 5,520
