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Lera25 [3.4K]
3 years ago
6

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

ct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers.
Find the lateral area the regular pyramid

Mathematics
1 answer:
iragen [17]3 years ago
3 0

Answer:

15

Step-by-step explanation:because u add them all up

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12 spheres of the same size are made from melting a solid cylinder of 1 cm diameter and 2 cm height. Find the diameter of each s
mars1129 [50]

The answer is: The diameter is 4 centimeters.

The explanation  is shown below:

1. The volume of the cylinder is:

Vc=r^{2}h \pi

Where r is the radius (r=\frac{16cm}{2}=8cm) and h is the height (h=2cm).

Then:

Vc=(8cm)^{2}}(2cm)\pi\\Vc=128\pi

2. The total volume of the 12 spheres is:

Vs=12(\frac{4}{3}r^{3}\pi)\\Vs=16r^{3}\pi

3. The volume of the cylinder and the total volume of all the 12 spheres, are equal, therefore:

Vc=Vs\\128\pi=16r^{3}\pi

4. Now, you must solve for the radius:

r=\sqrt[3]{\frac{128\pi}{16\pi}}\\r=2cm

5. The diameter is:

d=2r\\d=2(2cm)\\d=4cm

5 0
3 years ago
Please help me I hate math
podryga [215]
The triangle classifies as a acute triangle.
3 0
3 years ago
Read 2 more answers
5. Find the value(s) of x so that the line containing the points (2x + 3, x + 2) and (0, 2) is
Dvinal [7]

Answer:

  x = -2 or -9

Step-by-step explanation:

You want the values of x such that the line defined by the two points (2x+3, x+2) and (0, 2) is perpendicular to the line defined by the two points (x+2, -3-3x) and (8, -1).

<h3>Slope</h3>

The slope of a line is given by the slope formula:

  m = (y2 -y1)/(x2 -x1)

Using the formula, the slopes of the two lines are ...

  m1 = (2 -(x+2))/(0 -(2x+3)) = (-x)/(-2x-3) = x/(2x +3)

and

  m2 = (-1 -(-3-3x))/(8 -(x+2)) = (2+3x)/(6 -x)

<h3>Perpendicular lines</h3>

The slopes of perpendicular lines have product of -1:

  \dfrac{x}{2x+3}\cdot\dfrac{2+3x}{6-x}=-1\\\\x(3x+2)=(2x+3)(x-6)\qquad\text{multiply by $(2x+3)(6-x)$}\\\\3x^2+2x=2x^2-9x-18\qquad\text{eliminate parentheses}\\\\x^2+11x+18=0\qquad\text{put in standard form}\\\\(x+2)(x+9)=0\qquad\text{factor}

<h3>Solutions</h3>

The values of x that satisfy this equation are x = -2 and x = -9. The attached graphs show the lines for each of these cases.

4 0
1 year ago
Which equation is y= 2x ^2 - 8x +9 rewritten in vertex form.
tankabanditka [31]
<span>y= 2x ^2 - 8x +9

</span>y = a(x - h)2 + k, where (h, k) is the vertex<span> of the parabola
</span>so
y= 2x ^2 - 8x + 9
y= 2x ^2 - 8x + 8 + 1
y = 2(x^2 - 4x - 4) + 1
y = 2(x - 2)^2 + 1 ....<---------<span>vertex form</span>
7 0
3 years ago
What is the answer for 2x-5+6
julsineya [31]
2x - 11 is the answer because you don’t know what x is equal to
5 0
3 years ago
Read 2 more answers
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