All categories

3 years ago

What is the nth term in the sequence: -5, -2 ,3 ,10 , 19 Please show working out

Mathematics

1 answer:

melamori03 [73]3 years ago

7 0

30? I think, I might be wrong

You might be interested in

Generate the first 7 terms of the sequence defined by Q = 3n+ 5.

d1i1m1o1n [39]

Answer:

8,11,14,17,20,23,26

Step-by-step explanation:

Q = 3n+ 5

an=3n+5

a1=3(1)+5=8

a2=3(2)+5=11

a(3)=3(3)+5=14

a4=3(4)+5=17

a5=3(5)+5=20

a6=23

a7=26

8 0

3 years ago

Please answer giving BRAINLIEST

Andreas93 [3]

Answer:

x=7

Step-by-step explanation:

You

Have

X-ray

Vision

YhXr

7 0

3 years ago

Find the value of the question mark

pogonyaev

Answer:

Step-by-step explanation:

4 0

3 years ago

The Questions above.

Sergeeva-Olga [200]

Answer:

It's B.9

Step-by-step explanation:

Because

11+9=20

20+9= 29

29+9= 38

The common difference is positive because the arithmetic sequence is increasing.

8 0

3 years ago

Read 2 more answers

Determine whether The given segments have the same length. Justify your answer

Semenov [28]

We know the distance formula is

$\sqrt{ (x_{2}-x_{1})^2+ (y_{2}-y_{1})^2 }$

Here A( -4,2) and B(1,4)

So length of AB

= $\sqrt{(1-(-4))^2+(4-2)^2} =\sqrt{5^2+2^2} =\sqrt{29}$

Also C(2,1)

Length of BC

= $\sqrt{(2-1)^2+(-1-4)^2} =\sqrt{1^2+(-5)^2} =\sqrt{26}$

So we can see that length of AB is not equal to length of BC

11.

Now AB = $\sqrt{29}$

Also C(2,-1) & D(4,4)

Length of CD

= $\sqrt{(4-2)^2+(4-(-1)) ^2} =\sqrt{2^2+5^2} =\sqrt{29}$

Yes AB = CD

5 0

3 years ago