Find the midpoint of the line segment with endpoints (10,-1) and (10,1)

What is the mean absolute deviation of the following data set

tatuchka [14]

Answer:

4.32

Step-by-step explanation:

First, we have to find the mean of the data set.

16, 11, 9, 12, 11, 10, 10, 8, 15, 0, 2, 15, 14, 7, 11, 5, 14, 20, 3, 11, 13, 7, 0, 5, 21 all added together equals 250. 250 divided by 25 = 10. So 10 is the mean.

Now we have to find the absolute distances of each number from the mean.

16 - 10 = 6... 11 - 10 = 1... so on, giving us this -->

6, 1, 1, 2, 1, 0, 0, 2, 5, 10, 8, 5, 4, 3, 1, 5, 4, 10, 7, 1, 3, 3, 10, 5, 11

Finally, we have to find the mean of the distances (which is done by adding all the numbers above and dividing the sum by the number of values there are).

108 divided by 25 = 4.32.

So, 4.32 is the mean absolute deviation (MAD) of the following data set.

4 0

3 years ago

The weight, in pounds , of Mike's five pet dogs are listed below.What is the mean absolute deviation (MAD) of the weights?

madreJ [45]

Answer:

it would be 32

Step-by-step explanation:

you would add them all up then divide it by five

7 0

3 years ago

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A rectangle has an area of 96 sq ft if the width of the yard is 4 ft less than the length, what is the perimeter in ft of the ya

Veronika [31]

The area of a rectangle is obtained through the equation,

A = L x W

The width of the yard is 4 ft less than the length and may be expressed as L - 4. Length may be solved through the following steps,

A = (L)(L-4) ; 96 = L(L - 4) ; L = 12 ft

The length and width are 12 ft and 8 ft, respectively. Perimeter may be solved through the equation,

P = 2 x (L + W)

Substituting the values of L and W

P = 2 x ( 12 ft + 8 ft) = 40 ft

Therefore, the perimeter of the yard is 40 ft.

6 0

3 years ago

How does the speed of a runner vary over the course of a marathon (a distance of 42.195 km)? Consider determining both the time

Tom [10]

Answer:

The observed typical difference value of mode is 100 seconds approximately.

The proportion of runners ran the late distance more quickly than the early distance is approximately 1%

Step-by-step explanation:

Fundamentals

Consider that there are x favorable cases to an event E, out of a total of n cases. Then, the probability of that event is written as:

P(E)=

Total number of cases /Number of favorable cases = x/n

A histogram is constructed for continuous data, which is divided into classes called bins. The shape of the distribution can be determined from the histogram.

step 1

The provided histogram indicates time difference on xx -axis and frequency of runners on yy -axis. To determine the typical difference value, identify the peaks of the graph.

The histogram is skewed towards right side. The graph indicates that there are few outliers around 700 seconds. For a typical difference value, the value of mode is considered.

The graph indicates that the value of mode is 100 seconds approximately.

The observed typical difference value of mode is 100 seconds approximately.

Explanation

From the histogram, the typical difference value is obtained on the basis of guessing the value of mode which has been approximated to be around 100 seconds.

Step 2

From the histogram, it can be estimated that there are around 10 runners which has negative difference which means approxi8matley 10 runners ran the late distance more quickly than the early distance,

The approximate sample size can be calculated as:

Sample size=90+190+180+160+120+80+60+40+30+20

Thus, the proportion of runners is obtained as:

\begin{array}{c}\\p = \frac{{\left( \begin{array}{l}\\{\rm{Number of runners who has }}\\\\{\rm{negative time difference}}\\\end{array} \right)}}{{{\rm{Total sample size}}}}\\\\ = \frac{{10}}{{970}}\\\\ = 0.01\\\end{array}

p= Number of runners who has

negative time difference

Total sample size

=10/970

=0.001

The proportion of runners ran the late distance more quickly than the early distance is approximately 1%

EXPLANATION

The obtained proportion is 0.01. It indicates that there are approximately 1% of the runners who ran late distance more quickly than the early distance is very few.

3 0

3 years ago

ABC is isosceles. m < a = 3x + 40 and m < c = x + 50 what is m < a ??

il63 [147K]

Answer:

55°

Step-by-step explanation:

It is assumed the angles A and C are congruent:

3x + 40 = x + 50
3x - x = 50 - 40
2x = 10
x = 5

m∠A = 3*5 + 40 = 55°

7 0

3 years ago

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