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Lorico [155]
3 years ago
7

27.346 in place value chart

Mathematics
2 answers:
Brums [2.3K]3 years ago
5 0
About a little bit more than an 1/2 between 27 and 28
Ivanshal [37]3 years ago
3 0
About 1/3 between 27 and 28
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Select the correct answer.
Shtirlitz [24]
Why are all the answer choices the same..?
7 0
3 years ago
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The probability is 0.4 that a traffic fatality involves an intoxicated or​ alcohol-impaired driver or nonoccupant. In 7 traffic​
Luden [163]

Answer:

a.

P(X=3)=0.2903\\\\P(X \geq  3)=0.5801\\\\P(X\leq 3)0.7102

b.

P(2\leq x\leq 4 )=0.7451

c. mean=2.8

d . standard deviation=1.2961

Step-by-step explanation:

We determine that the accident rates follow a binomial distribution. The rate of success p=0.4 and sample n=7:

P(x)={n\choose x}p^x(1-p)^{n-x}

#the probability of exactly​ three;

P(x)={n\choose x}p^x(1-p)^{n-x}\\\\P(X=3)={7\choose 3}0.4^3(0.6)^{4}\\\\=0.2903

#At least(more than 2)

P(x)={n\choose x}p^x(1-p)^{n-x}\\\\P(X\geq 3)=1-P(X\leq 2)\\\\=1-{7\choose 0}0.4^0(0.6)^{7}-{7\choose 1}0.4^1(0.6)^{6}-{7\choose 2}0.4^2(0.6)^{5}\\\\=1-0.0280-0.1306-0.2613\\\\=0.5801

#At most 3;

P(x)={n\choose x}p^x(1-p)^{n-x}\\\\P(X \leq 3)={7\choose 0}0.4^0(0.6)^{7}+{7\choose 1}0.4^1(0.6)^{6}+{7\choose 2}0.4^2(0.6)^{5}+{7\choose 3}0.4^3(0.6)^{4}\\\\\\\=0.0280+0.1306+0.2613+0.2903\\\\=0.7102

b. Between 2 and 4:

Using the binomial expression, this probability is calculated as:

P(x)={n\choose x}p^x(1-p)^{n-x}\\\\P(2\leq x\leq 4 )={7\choose 2}0.4^2(0.6)^{5}+{7\choose 3}0.4^3(0.6)^{4}+{7\choose 4}0.4^4(0.6)^{3}\\\\\\\\\=0.2613+0.2903+0.1935\\\\=0.7451

Hence,the probability of between 2 and four is 0.7451

c. From a above, we have the values of n=7 and p=0.4.

-We substitute this values in the formula below to calculate the mean:

-The mean of a binomial distribution is calculated as the product of the probability of success by the sample size, mean=np:

\mu=np, n=7, p=0.4\\\\\mu=7\times 0.4\\\\=2.8

Hence, the standard deviation of the sample is 2.8

d. From a above, we have the values of n=7 and p=0.4

--We substitute this values in the formula below to calculate the standard deviation

-The standard deviation a binomial distribution is given as:

\sigma={\sqrt {np(1-p)}\\\\=\sqrt{7\times 0.4\times 0.6}\\\\=1.2961

Hence, the standard deviation of the sample is 1.2961

4 0
3 years ago
Find the average of 37, 36, 76, 84 and 37.
Strike441 [17]

Answer:

The average(mean) is 54

Add 37, 36, 76, 84 and 37, then divide by 5

Step-by-step explanation:

Hope this helps!!! :))

8 0
3 years ago
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Suppose that MNO is isosceles with base NM. Suppose also that =m∠N+4x7° and =m∠M+2x29°. Find the degree measure of each angle in
chubhunter [2.5K]

Answer:

m∠N = 51°

m∠M = 31°

m∠O = 98°

Step-by-step explanation:

It is given that ΔMNO is an isosceles triangle with base NM.

m∠N = (4x + 7)° and m∠M = (2x + 29)°

By the property of an isosceles triangle,

Two legs of an isosceles triangle are equal in measure.

ON ≅ OM

And angles opposite to these equal sides measure the same.

m∠N = m∠M

(4x + 7) = (2x + 29)

4x - 2x = 29 - 7

2x = 22

x = 11

m∠N = (4x + 7)° = 51°

m∠M = (2x + 9)° = 31°

m∠O = 180° - (m∠N + m∠M)

         = 180° - (51° + 31°)

         = 180° - 82°

         = 98°

8 0
3 years ago
A spherical balloon is inflated with a gas at the rate of 500 cm3/min. How fast is the radius of the balloon increasing at the i
Burka [1]

The volume of the sphere is expressed in the formula V = 4/3 pi r^3. The rate of change of volume is determined by differentiating the formula: dV/dt = 4pi r^2 dr/dt. When we substitute 500 cm3/min as dV/dt and 30 cm as r. Then dr/dt is equal to 0.0442 cm/min
7 0
4 years ago
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