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2 years ago

Please show your work, I'd really appreciate the help! :)

Mathematics

1 answer:

xenn [34]2 years ago

3 0

Y=12.5+1.25X , this is how youget the fair admission amount 43.75-(25x1.25)=12.5

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Please help! Three step linear equations

zzz [600]

Answer:

I solved it and my answer is - 2

Step-by-step explanation:

5x+6=8x+12

5x-8x =12 - 6

-3x =6

Divide by - 3

X=-2

6 0

2 years ago

Pierre wants to make tables and chairs. He has a total of 220 wooden boards and 760 nails. 13T+8C≤220 represents the number of t

Alisiya [41]

Answer:

Pierre has enough boards and nails to make 9 tables and 5 chairs.

Step-by-step explanation:

13T+8C ≤ 220

Let us substitute 9 for T and 5 for C and check.

13(9) + 8(5) = 117 + 40

= 157 < 220

So, 220 wooden boards are sufficient to make 9 tables and 5 chairs.

48T+37C ≤ 760

Substitute 9 for T and 5 for C.

48(9)+37(5) = 432 + 185

= 617 < 760

So, 760 nails are sufficient to make 9 tables and 5 chairs.

Hence, Pierre has enough boards and nails to make 9 tables and 5 chairs.

3 0

2 years ago

Solve r + (-8) = 10<br><br> ———————-

Yuliya22 [10]

Answer:

r = 18

Step-by-step explanation:

r -8 = 10

r -8 + 8 = 10 + 8

r = 18

4 0

3 years ago

THERE ARE 3 BAGS OF APPLES WEIGHING A TOTAL OF 22 1/2 POUNDS. TWO OF THE BAGS WEIGH 6 3/8 POUNDS AND 3 1/4 POUNDS. HOW MUCH DOES

Mkey [24]

I wasn't going to click on this one, but the all-caps enthralled me and hypnotized me.

first off, let's change all the mixed fractions to "improper" and proceed from there, keep in mind that if we subtract the two bags' weight from the total, what's leftover is the 3rd bag's weight.

$\bf \stackrel{mixed}{22\frac{1}{2}}\implies \cfrac{22\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{45}{2}}
\\\\\\
\stackrel{mixed}{6\frac{3}{8}}\implies \cfrac{6\cdot 8+3}{8}\implies \stackrel{improper}{\cfrac{51}{8}}
\\\\\\
\stackrel{mixed}{3\frac{1}{4}}\implies \cfrac{3\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{13}{4}}\\\\
-------------------------------\\\\$

$\bf \stackrel{\textit{sum of the two bags}}{\cfrac{51}{8}+\cfrac{13}{4}}\impliedby \textit{our LCD is 8}\implies \cfrac{(1)51+(2)13}{8}
\\\\\\
\cfrac{51+26}{8}\implies \cfrac{77}{8}\\\\
-------------------------------\\\\
\stackrel{total}{\cfrac{45}{2}}~-~\stackrel{two~bags}{\cfrac{77}{8}}\impliedby \textit{our LCD is again 8}\implies \cfrac{(4)45-(1)77}{8}
\\\\\\
\cfrac{180~~-~~77}{8}\implies \cfrac{103}{8}\implies \stackrel{third~bag}{12\frac{7}{8}}$

3 0

3 years ago

Q7. Average of 60 numbers are 55. When 10 more numbers are included, the average of

Nikitich [7]

Answer:

The average of the 10 numbers is 195

Step-by-step explanation:

The average of a set of numbers is the sum of the numbers dividing by their number

Average = The sum ÷ The number

∵ The average of 60 numbers is 55

∴ The average = 55

∴ The number = 60

→ Substitute them in the rule above to find the sum of the numbers

∵ 55 = The sum ÷ 60

→ Multiply each side by 60

∴ 3300 = The sum

∴ The sum of the 60 numbers = 3300

∵ 10 more numbers are included

∵ The average of 70 numbers become 75

∴ The average = 75

∴ The number = 70

→ Substitute them in the rule above to find the sum of the numbers

∵ 75 = The sum ÷ 70

→ Multiply each side by 70

∴ 5250 = The sum

∴ The sum of the 70 numbers = 5250

∵ The sum of the 10 numbers that added is the difference between

the sums of the 60 and 70 numbers

∵ The difference between the sums = 5250 - 3300

∴ The difference between the sums = 1950

→ To find the average of them divide their sum by 10

∵ The average of the 10 numbers = 1950 ÷ 10

∴ The average of the 10 numbers = 195

5 0

3 years ago