Answer:

Step-by-step explanation:

Adding and Subtracting 1 to the Numerator

Dividing Numerator seperately by 

Here integral of 1 is x +c1 (where c1 is constant of integration
----------------------------------(1)
We apply method of partial fractions to perform the integral
=
------------------------------------------(2)

1 =
-------------------------(3)
Substitute x= 1 , -1 , i in equation (3)
1 = A(1+1)(1+1)
A = 
1 = B(-1-1)(1+1)
B = 
1 = C(i-1)(i+1)
C = 
Substituting A, B, C in equation (2)
= 
On integration
Here 
=
-
-
+ c2---------------------------------------(4)
Substitute equation (4) back in equation (1) we get

Here c1 + c2 can be added to another and written as c
Therefore,
