Can someone help, please? Will mark Brainliest.

For THE LAST TIME CAN SOMEONE PLEASE I BEG YOU AND HELP ME BEFORE I FAINT BECAUSE I HAVE BEEN WORKING ON THIS SINCE THE MORNING

Lynna [10]

I gotchu my guy let me know what you need help with I’d gladly revive those free points

3 0

3 years ago

If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?

lys-0071 [83]

Answer:

2

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

$3x^2-(3k-2)x-(k-6) \text{ with }k=2$ :

$3x^2-(3\cdot 2-2)x-(2-6)$

$3x^2-4x+4$

I'm going to solve $3x^2-4x+4=0$ for x using the quadratic formula:

$\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}$

$\frac{4\pm \sqrt{16-16(3)}}{6}$

$\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}$

$\frac{4\pm 4\sqrt{-2}}{6}$

$\frac{2\pm 2\sqrt{-2}}{3}$

$\frac{2\pm 2i\sqrt{2}}{3}$

Let's see if uv=u+v holds.

$uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}$

Keep in mind you are multiplying conjugates:

$uv=\frac{1}{9}(4-4i^2(2))$

$uv=\frac{1}{9}(4+4(2))$

$uv=\frac{12}{9}=\frac{4}{3}$

Let's see what u+v is now:

$u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}$

$u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}$

We have confirmed uv=u+v for k=2.

4 0

3 years ago

If f(x)=3x^2 and g(x)=4x^3, what is the degree of (f*g)(x)?

Westkost [7]

3x^2 * 4x^3 = 12x^5

Answer is degree 5

3 0

3 years ago

Read 2 more answers

A bee flew 840 \text{ cm}840 cm840, space, c, m and landed on a flower to collect some pollen. Then the bee flew another 330 \te

alexdok [17]

Answer:

The bee traveled 11.7 meters.

Step-by-step explanation:

A bee flew 840 cm first to land on a flower to collect some pollen and then flew another 330 cm to get back to her hive.

For finding the total distance traveled, we need to just add 840 cm and 330 cm.

So, $(840+330) cm = 1170 cm$

We know that, 1 meter = 100 cm. That means, for converting 'cm' into 'meter' , we need to divide by 100.

Thus, $1170 cm= \frac{1170}{100} meter = 11.7 meter$

So, the bee traveled 11.7 meters.

5 0

3 years ago

Five friends are leaving a bar for home. Aside from the owner of the car, one other person is deemed able to operate the vehicle

erastova [34]

Answer:

4

Step-by-step explanation:

one person is deemed to drive and that person is fixed on the driver's seat no mater which arrangement.

we have now 2 more seats one adjacent to the driver and one rear (two combined).

so the total ways in which all five can be arranged is as follows.

driver, adjacent to him(1) and three back.

driver adjacent to him (different person) and three back.

see the driver is always fixed so we can ignore him.

thus we when driver set fixed , on two remaining seats (adjacent to driver and the back )there can be 4 different combinations.

3 0

3 years ago