What number should be removed from the list {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13} so that the mean of the remaining number
1 answer:
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step by step explanation:
=[x2+16=0x26]
=[2x{y}^2{16}~0]
=[4×{y}^0{16}]
=[32x{y}^x]
Answer:
Step-by-step explanation:
Given equation:
Since 5 is the greatest common factor of 65 and 60 in the given expression.
Therefore, the above expression can be written as
Hence, by factoring the side that contains the variable p we have the expression .
Answer:
a) There is a 1.21% probability that both contain diet soda.
b) There is a 79.21% probability that both contain diet soda.
c) is unusual,
is not unusual
d) There is a 19.58% probability that exactly one is diet and exactly one is regular.
Step-by-step explanation:
There are only two possible outcomes. Either the can has diet soda, or it hasn't. So we use the binomial probability distribution.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinatios of x objects from a set of n elements, given by the following formula.
And is the probability of X happening.
A number of sucesses is considered unusually low if
and unusually high if
In this problem, we have that:
Two cans are randomly chosen, so
Two out of 18 cans are filled with diet coke, so
a) Determine the probability that both contain diet soda. P(both diet soda)
That is P(X = 2).
There is a 1.21% probability that both contain diet soda.
b)Determine the probability that both contain regular soda. P(both regular)
That is P(X = 0).
There is a 79.21% probability that both contain diet soda.
c) Would this be unusual?
We have that is unusual, since
For P(X = 0), it is not unusually high nor unusually low.
d) Determine the probability that exactly one is diet and exactly one is regular. P(one diet and one regular)
That is P(X = 1).
There is a 19.58% probability that exactly one is diet and exactly one is regular.