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stich3 [128]
3 years ago
6

What is the area of rectangle ABCD?

Mathematics
2 answers:
Fed [463]3 years ago
7 0

Answer:

8 sq. units

Step-by-step explanation:

Length of AD= BC= 4 units

length of CD= AB= 2 units

Area of Rectangle ABCD = LENGTH× BREADTH

= 4×2= 8 sq. units

azamat3 years ago
3 0

Answer:

24

Step-by-step explanation:

I learned this in like 5th grade

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If a car averages 21.8 miles per gallon, how many miles will it travel on 16 gallons of gas?
asambeis [7]

Answer: 348.8 miles on 16 gallons of gas

Step-by-step explanation:

Make the following proportion:

\frac{21.8 miles}{1 gallon} = \frac{x miles}{16 gallons}

Since the car consumes gas at the same rate and only the amount of gas is changed, these two fractions must be equivalent. If the rate at which the car consumes gas changes, it would be different.

Use basic algebraic skills and you should get 348.8 miles.

7 0
2 years ago
The following prices, in dollars, of 7.5-cubic-foot refrigerators were recorded from a random sample. 314 305 344 283 285 310​ 3
Mariana [72]

Answer:

t=\frac{310.9-300}{\frac{31.09}{\sqrt{10}}}=1.109      

The degrees of freedom are given by:

df=n-1=10-1=9  

And the p value would be given by:

p_v =P(t_{9}>1.109)=0.148  

Since the p value is higher than the significance level of 0.05 we don't have enough evidence to conclude that the true mean is significantly higher than $300 because we FAIL to reject the null hypothesis.

Step-by-step explanation:

Information given

314 305 344 283 285 310​ 383​ 285​ 300​ 300

We can calculate the sample mean and deviation with the following formula:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

s =\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}}

\bar X=310.9 represent the sample mean      

s=31.09 represent the standard deviation for the sample      

n=10 sample size      

\mu_o =300 represent the value to test

\alpha=0.05 represent the significance level

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to verify if the true mean is greater than 300, the system of hypothesis would be:      

Null hypothesis:\mu \leq 300      

Alternative hypothesis:\mu > 300      

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)      

Replacing the info given we got:

t=\frac{310.9-300}{\frac{31.09}{\sqrt{10}}}=1.109      

The degrees of freedom are given by:

df=n-1=10-1=9  

And the p value would be given by:

p_v =P(t_{9}>1.109)=0.148  

Since the p value is higher than the significance level of 0.05 we don't have enough evidence to conclude that the true mean is significantly higher than $300 because we FAIL to reject the null hypothesis.

6 0
3 years ago
The distance between port M and port N is 162m. A ship left port M with a speed of 45 mph. In 45 minutes another ship left port
matrenka [14]

Answer:

After 900 minutes

Step-by-step explanation:

when we convert the velocities of the ships into miles/ min we get

45mph=45m/60min=0.75m/min

36mph=36m/60min=0.6m/min

The equations determining the distances  of the ships from the port M (set at x=0) are

D_1=0.75t (for 45mph ship)

D_2=162+0.6(t-45) (for 36mph ship)

The solution to these equation lie at t= 900 minutes; therefore the two ships will meet 900 minutes after the departure of the first ship.

8 0
3 years ago
Read 2 more answers
Solve. Justify your responses. a Given:a║b and c║d, m∠ 4=35° Find: m∠1, m∠2, and m∠3
STALIN [3.7K]

Answer:

<em>m∠1 =  90°</em>

<em>m∠2 = 35°</em>

<em>m∠3 = 55°</em>

Step-by-step explanation:

Find the diagram attached

From the diagram:

m

Given that <4 = 35°

m

The sum of the angle on a straight line at point A is 180°. Hence:

90+m

The sum of angle in the triangle ABC is 180°, hence;

m

7 0
2 years ago
If a positive integer that is not a multiple of 5 is divided by 5, what is the least possible remainder
solniwko [45]
I would say 1 would be the least possible remainder...

11/5 = 2 remainder 1
21/5 = 4 remainder 1
31/5 = 3 remainder 1

and since ur dealing with positive integers (whole numbers), 1 is gonna be the smallest
8 0
3 years ago
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