Answer:
An equation for each situation, in terms of x
A = 35 + 3x
B = 80 + 2x
The interval of miles driven x, for which Company A is cheaper than Company B is 0 to 44.9 miles.
Step-by-step explanation:
Let A represent the amount Company A would charge if Piper drives x miles
Let B represent the amount Company B would charge if Piper drives x miles.
Company A charges an initial fee of $35 for the rental plus $3 per mile driven.
A= $35 + $3 × x
A = 35 + 3x
Company B charges an initial fee of $80 for the rental plus $2 per mile driven.
B = $80 + $2 × x
B = 80 + 2x
The interval of miles driven x, for which Company A is cheaper than Company B.
= A < B
35 + 3x < 80 + 2x
3x - 2x < 80 - 35
x < 45 miles
That is: any number of miles driven below 45 miles makes Company A cheaper than Company B
The interval of miles driven x, for which Company A is cheaper than Company B is 0 to 44.9 miles.
Answer:
x = 2, -3
Step-by-step explanation:
(x-2) = 0 or (x+3) = 0
x = 2 or x = -3
Thus, two values of x are x = 2, -3
Note: The options given are incorrect.
This is a linear relationship. The slope-intercept form of the linear equation is:
Where,
- m is the rate of change (positive if increasing rate and negative if decreasing rate)
- c is the y intercept, or the initial value
<u><em>Rate of change is 2.5 quarts per minute (it is decreasing so m is -2.5)</em></u>
<u><em>Initial value is 50 quarts, so c is 50.</em></u>
Plugging in the values we get 
.
Changing variables to w instead of y and t instead of x, gives us,
. Where w is warts of water left in the tub and t is the time in minutes.
There is no viable solution when t=30 because at t=20, w=0 (
). It means after 20 minutes, there is no water left. So t=30 minutes doesn't make sense.
ANSWER:
Modelling equation:
When 
, there is no VIABLE solution
Answer:vssbiubpu buivbub [u bu[b [uib
Step-by-step explanation:
scewsucpsivgeduaigxuygu1yuwgyugvuygquyy3gvdv
Answer:
the remaining money is $1189.22
Step-by-step explanation:
