I think that can help for now
a + m = 30
a = m - 8
(m - 8) + m = 30
2m - 8 = 30
2m = 30 + 8
2m = 38
m = 38/2
m = 19
a = m - 8
a = 19 - 8
a = 11
so Amy has $11 and Maria has $ 19
The first 3 are examples of the difference of 2 squares so you use the identity
a^2 - b^2 = (a + b)(a - b)
x^2 - 49 = 0
so (x + 7)(x - 7) = 0
so either x + 7 = 0 or x - 7 = 0
giving x = -7 and 7.
Number 7 reduces to 3x^2 =12, x^2 = 4 so x = +/- 2
Number 8 take out GCf (d) to give
d(d - 2) = 0 so d = 0 , 2
9 and 10 are more difficult to factor
you use the 'ac' method Google it to get more details
2x^2 - 5x + 2
multiply first coefficient by the constant at the end
that is 2 * 2 = 4
Now we want 2 numbers which when multiplied give + 4 and when added give - 5:- -1 and -4 seem promising so we write the equation as:-
2x^2 - 4x - x + 2 = 0
now factor by grouping
2x(x - 2) - 1(x - 2) = 0
(x - 2) is common so
(2x - 1)(x - 2) = 0
and 2x - 1 = 0 or x - 2 = 0 and now you can find x.
The last example is solved in the same way.
X - 7 > 10
x > 10 + 7
x > 17
3x < = 21
x < = 21/3
x < = 7
5a - 2 < 18
5a < 18 + 2
5a < 20
a < 20/5
a < 4
2t + 8 > = -4 (t + 1)
2t + 8 > = -4t - 4
2t + 4t > = -4 - 8
6t > = - 12
t > = -12/6
t > = -2
Answer:I believe it is 2.4
Step-by-step explanation:
