The answer is 79 and 80.
x - the number of the first locker
x + 1 - the number of the consecutive locker
Their sum is 159.
x + x + 1 = 159
2x + 1 = 159
2x = 159 - 1
2x = 158
x = 158 / 2
x = 79
x - the number of the first locker: x = 79
x + 1 - the number of the consecutive locker x + 1 = 79 + 1 = 80
Answer:
the second chaise is the answer
Material=wall+2*side and material is 40 ft so:
40=w+2s
w=40-2s
Area=ws, using w from above we get:
A=(40-2s)s
A=40s-2s^2
dA/ds=40-4s and d2A/ds2=-4
Since d2A/ds2 is a constant negative acceleration, when dA/ds=0, A(s) is at an absolute maximum.
dA/ds=0 when 4s=40, s=10 ft
And since w=40-2s, w=20 ft
So the dimensions of the pen are 20 ft by 10 ft, with the 20 ft side being opposite the wall. And the maximum possible area is thus 200 ft^2
Answer:
use desmos it will help you with plots
Step-by-step explanation:
just search desmos
Answer:
integer = 5
rational number but not an integer - 3 and a 1/2
irrational number - it's the one with 11
