La ecuación que nos dice cuantas niñas hay en el colegio es:
A = x - c*m
¿Como encontrar una expresión para la cantidad de niñas?
Sabemos que hay un total de x estudiantes, definimos las variables:
- A = cantidad total de niñas
- B = cantidad total de niños.
Entonces tenemos A + B = x
Tambien sabemos que los estudiantes estan divididos en c cursos, de tal forma que hay m niños por curso.
Entonces c por m es igual a la cantidad total de niños:
c*m = B
Reemplazando esto en la ecuación de arriba podemos obtener:
A + c*m = x
A = x - c*m
Esta es la ecuación que nos da el numero total de niñas en el colegio.
Sí quieres aprender más sobre ecuaciones, puedes leer:
brainly.com/question/18168483
Answer:
Step-by-step explanation:
hi: the second, the third and the last one are true
X+8>= 18
therefore, the circle has to be on ten, (solid) and an arrow pointing to the right,
10+8>=18 which is true.
-7+x>= -8
the circle is going to be on -1, (solid) and pointing to the right.
-7 +-1 (-8) >=-8 which is true, then -7 +0>= -8 which is true
n-2<=4 so, the answer is a dot (solid) on 6 pointing to the left
6-2 (4) <=4 then 5-2 (3) <= 4 which both are true
-18+n<-7
so this answer is going to be on 10, and it will be a hollow dot, pointing to the left
-18+10 (-8) <-7 which is true
n-4>=13
so, this has to be greater than or equal to 13.
n must be greater than or equal to 17 (add 4 to both sides) so the dot (solid) is going to be on 17 and pointing to the right.
NOTICE: I had a different explanation for number 9, which is how I figured each one out.
Hope this helped! Sorry it took so long!
Answer:
-32p +56
Step-by-step explanation:
distribute the 8 to everything in the parenthesis
Answer:
The box-and-whisker plot for the given question is as shown at the attached figure.
Minimum = 11
Lower quartile = Q1 = 12
Median = Q2 = 23.5
Upper quartile = Q3 = 27
Maximum = 33
<u>So, according to the given data and the figure:</u>
- The box will go from <u>12 to 27</u> ⇒ Q1 to Q3
- A line dividing the box will go at <u>23.5</u> ⇒ Q2
- The left whisker will go from <u>11 to 12</u> ⇒ Minimum to Q1
- The right whisker will go from to <u>27 to 33</u> ⇒ Q2 to Maximum