Question

The length of a rectangle is 15 and its width is w.

Answer 1

A rectangle with sides 15 and w has perimeter

$2p = 2(15+w) = 2w+30$

We want this quantity to be at most 50, so it must be less than or equal to 50:

$2w+30\leq 50$

For the record, this implies that

$2w\leq 20 \iff w \leq 10$

So, the width can be at most 10.

Answer 2

Answer:

2x+30< 50   ...answer : A

Step-by-step explanation:

the perimeter is :  P = 2(L+W)

let : L= x   given : L=15

P= 2(x+15)

The perimeter of the rectangle is, at most, 50:   P<50

2(x+15) < 50

2x+30< 50   ...answer : A