A rectangle with sides 15 and w has perimeter
We want this quantity to be at most 50, so it must be less than or equal to 50:
For the record, this implies that
So, the width can be at most 10.
Answer:
2x+30< 50 ...answer : A
Step-by-step explanation:
the perimeter is : P = 2(L+W)
let : L= x given : L=15
P= 2(x+15)
The perimeter of the rectangle is, at most, 50: P<50
2(x+15) < 50
Step 1: Simplify both sides of the equation.
−36=p−30
Step 2: Flip the equation.
p−30=−36
Step 3: Add 30 to both sides.
p−30+30=−36+30
p=−6
11.333 infinity
when you divide 34 by 3 you then get 11.3 infinity which would also be a repeating decimal
the answer is 3/7
