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4 years ago

Find the common difference of the arithmetic sequence -13,-16,-19,

Mathematics

1 answer:

marshall27 [118]4 years ago

6 0

Answer:

common difference=-3

Step-by-step explanation:

$- 13 - ( - 16) = - 13 + 16 = - 3$

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Hey please help with these algebra problems. THANKS!

____ [38]

Answer:

1 is correct for d

2 is the is no solution

not sure if I'm right been awhile since i did math so sorry if I'm wrong

Step-by-step explanation:

7 0

3 years ago

A lab animal may eat any one of three foods each day. Laboratory records show that if the animal chooses one food on one trial,

Tresset [83]

Answer:

The probability that it will choose food #2 on the second trial after the initial trial = 0.3125

Step-by-step explanation:

Given - A lab animal may eat any one of three foods each day. Laboratory records show that if the animal chooses one food on one trial, it will choose the same food on the next trial with a probability of 50%, and it will choose the other foods on the next trial with equal probabilities of 25%.

To find - If the animal chooses food #1 on an initial trial, what is the probability that it will choose food #2 on the second trial after the initial trial?

Proof -

By the given information, we get the stohastic matrix

$H = \left[\begin{array}{ccc}0.5&0.25&0.25\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right]$

As we know that,

The matrix is a Markov chain $x_{k+1} = Hx_{k}$

Let

The initial state vector be

$x_{0} = \left[\begin{array}{ccc}1\\0\\0\end{array}\right]$

we choose this initial vector because given that If the animal chooses food #1 on an initial trial.

Now,

$x_{1} = Hx_{0} \\ = \left[\begin{array}{ccc}0.5&0.25&0.25\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right]\left[\begin{array}{ccc}1\\0\\0\end{array}\right] \\= \left[\begin{array}{ccc}0.5\\0.25\\0.25\end{array}\right]$

∴ we get

$x_{1} = \left[\begin{array}{ccc}0.5\\0.25\\0.25\end{array}\right]$

Now,

$x_{2} = Hx_{1} \\ = \left[\begin{array}{ccc}0.5&0.25&0.25\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right]\left[\begin{array}{ccc}0.5\\0.25\\0.25\end{array}\right] \\= \left[\begin{array}{ccc}0.25+0.0625+0.0625\\0.125+0.125+0.0625\\0.125+0.0625+0.125\end{array}\right]\\= \left[\begin{array}{ccc}0.375\\0.3125\\0.3125\end{array}\right]$

∴ we get

$x_{2} = \left[\begin{array}{ccc}0.375\\0.3125\\0.3125\end{array}\right]$

∴ we get

The probability that it will choose food #2 on the second trial after the initial trial = 0.3125

4 0

3 years ago

Use inverse operations to love each equation--

Dominik [7]

a.) you start with 19=h/3-8 so you add 8 to both sides then you simplify 19+8 to 27 so the equation then becomes 27=h/3 from there you multiply each side by 3 so its 27*3=h then you simplify 27*3 which leaves you with 81=h u then switch it around and your final answer h=81

b.) you start with 0.6x +0.8=1.4 first you subtract 0.8 from both sides so the equation is 0.6x=1.4-0.8 then you simplify 1.4-0.8/ so it then becomes 0.6x=0.6 u then divide both sides by 0.6 so the equation is now x=0.6/0.6 you then simplify 0.6/0.6 so you are left with x=1

7 0

3 years ago

The aspect ratio (the ratio of screen width to

stira [4]

Answer:

$Width = 36in$