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sergeinik [125]
4 years ago
7

Solve for the variable. Show all work. 8(1 - x) + 36 = -2(4x + 24) + 95

Mathematics
2 answers:
nlexa [21]4 years ago
8 0

remember that you can do anything to an equation as long as you do it to both sides

8(1-x)+36=-2(4x+24)+95

distribute

8-8x+36=-8x-48+95

-8x+44=-8x+47

add 8x to both sides

44=47

false

since the variables dissapeared and we were left with a false statement, no value of x will satisfy the equation


x={} (the empty set, no solution)

Troyanec [42]4 years ago
4 0

This statement is false, there is no variable to make this statement true.


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Fiona and Pip win some money and share it in the ratio 6:1. Fiona gets £35 more than Pip. How much did they get altogether?
Softa [21]

\boxed{ \mathfrak { question↷}}

Fiona and Pip win some money and share it in the ratio 6:1. Fiona gets £35 more than Pip. How much did they get altogether?

\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}

\boxed{ \mathfrak { solution↷}}

Let Pip get be x and fiona get be x+35

Ratio = 6:1

\tt \frac{x + 35}{x }  = 6

\tt \: x + 35 = 6x

\tt \: 5x = 35

\tt \: x = 7

\boxed{ \sf \: Total  \: money = x + x + 35 = 14+ 35 = £49}

3 0
2 years ago
Consider the probabilities of people taking pregnancy tests. Assume that the true probability of pregnancy for all people who ta
Valentin [98]

Using conditional probability, it is found that there is a 0.8462 = 84.62% probability that a woman who gets a positive test result is truly pregnant.

<h3>What is Conditional Probability?</h3>

Conditional probability is the probability of one event happening, considering a previous event. The formula is:

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem, the events are:

  • Event A: Positive test result.
  • Event B: Pregnant.

The probability of a positive test result is composed by:

  • 99% of 10%(truly pregnant).
  • 2% of 90%(not pregnant).

Hence:

P(A) = 0.99(0.1) + 0.02(0.9) = 0.117

The probability of both a positive test result and pregnancy is:

P(A \cap B) = 0.99(0.1)

Hence, the conditional probability is:

P(B|A) = \frac{0.99(0.1)}{0.117} = 0.8462

0.8462 = 84.62% probability that a woman who gets a positive test result is truly pregnant.

You can learn more about conditional probability at brainly.com/question/14398287

7 0
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