One of the properties of a parallelogram is that its opposite sides are parallel and congruent.
Segment AB and CD are opposite sides of the parallelogram and is therefore, congruent.
Therefore, the reason for CD≅ AB is: "Opposite sides of a parallelogram/rhombus/rectangle/square are congruent."
For the next statement, since CD≅AB and AB≅CE, then by Transitive Property, CD≅CE.
Since CD and CE are sides of a triangle and are congruent as stated in Statement 3, then ∠E ≅ ∠CDE because in a triangle, angles opposite of congruent sides are congruent.
In addition, we can say that ∠A ≅ ∠CDE because parallel lines (AB and CD) cut by a transversal (AE) form congruent corresponding angles.
Lastly, since ∠A ≅ ∠CDE and ∠CDE ≅ ∠E, we can say that ∠A ≅ ∠E by Transitive Property.
Answer:
19
Step-by-step explanation:
15z-14z=12+7
z=19
Hello from MrBillDoesMath!
Answer:
No. That problem cited is one of 3 great unsolved problems of antiquity. See https://en.wikipedia.org/wiki/Angle_trisection for details.
Regards,
MrB
P.S. I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!
Answer:
40 ft
Step-by-step explanation:
The maximum height of the ball is the y- coordinate of the vertex
Given a parabola in standard form then the x- coordinate of the vertex is
= -
h(t) = - 16t² + 48t + 4 ← is in standard form
with a = - 16, b = 48 , thus
= - = 1.5
Substitute t = 1.5 into h(t) for max. height
h(1.5) = - 16(1.5)² + 48(1.5) + 4
= - 36 + 72 + 4
= 40