What is 660 yds converted to mi and the process?

A doctor prescribes 150 milligrams of a therapeutic drug that decays by about 15% each hour. To the nearest hour, what is the ha

Nikolay [14]

Answer:

4 hours

Step-by-step explanation:

The amount remaining at the end of each hour is 0.85 of the amount at the start of the hour. You want to find the exponent such that ...

... 0.85^x = 0.5 . . . . . x = the number of hours until half is left

... x·log(0.85) = log(0.5) . . . . . take the log to turn it to a linear equation

... x = log(0.5)/log(0.85) ≈ 4.265024

Rounded to the nearest hour, x = 4.

3 0

2 years ago

Claire runs a rooftop nursery in the heart of the city. One day, she cuts 25 tulips, 32 violets, and 40 sunflowers. She sells th

jekas [21]

Answer:

(2) and (3)

Step-by-step explanation:

(2) shows the total cost of the flowers, minus 10% of the total cost, and 100% - 10% = 90%

(3) shows them taking 90% of the total cost, just like (2)

4 0

2 years ago

What is the answer for 16 + b = a<br>

Nitella [24]

Answer:

16

Step-by-step explanation:

i hope this helps

3 0

2 years ago

Consider the equation and the relation “(x, y) R (0, 2)”, where R is read as “has distance 1 of”. For example, “(0, 3) R (0, 2)”

Leviafan [203]

Answer:

The equation determine a relation between x and y

x = ± $\sqrt{1-(y-2)^{2}}$

y = ± $\sqrt{1-x^{2}}+2$

The domain is 1 ≤ y ≤ 3

The domain is -1 ≤ x ≤ 1

The graphs of these two function are half circle with center (0 , 2)

All of the points on the circle that have distance 1 from point (0 , 2)

Step-by-step explanation:

* Lets explain how to solve the problem

- The equation x² + (y - 2)² and the relation "(x , y) R (0, 2)", where

R is read as "has distance 1 of"

- This relation can also be read as “the point (x, y) is on the circle

of radius 1 with center (0, 2)”

- “(x, y) satisfies this equation , if and only if, (x, y) R (0, 2)”

* <em>Lets solve the problem</em>

- The equation of a circle of center (h , k) and radius r is

(x - h)² + (y - k)² = r²

∵ The center of the circle is (0 , 2)

∴ h = 0 and k = 2

∵ The radius is 1

∴ r = 1

∴ The equation is ⇒ (x - 0)² + (y - 2)² = 1²

∴ The equation is ⇒ x² + (y - 2)² = 1

∵ A circle represents the graph of a relation

∴ The equation determine a relation between x and y

* Lets prove that x=g(y)

- To do that find x in terms of y by separate x in side and all other

in the other side

∵ x² + (y - 2)² = 1

- Subtract (y - 2)² from both sides

∴ x² = 1 - (y - 2)²

- Take square root for both sides

∴ x = ± $\sqrt{1-(y-2)^{2}}$

∴ x = g(y)

* Lets prove that y=h(x)

- To do that find y in terms of x by separate y in side and all other

in the other side

∵ x² + (y - 2)² = 1

- Subtract x² from both sides

∴ (y - 2)² = 1 - x²

- Take square root for both sides

∴ y - 2 = ± $\sqrt{1-x^{2}}$

- Add 2 for both sides

∴ y = ± $\sqrt{1-x^{2}}+2$

∴ y = h(x)

- In the function x = ± $\sqrt{1-(y-2)^{2}}$

∵ $\sqrt{1-(y-2)^{2}}$ ≥ 0

∴ 1 - (y - 2)² ≥ 0

- Add (y - 2)² to both sides

∴ 1 ≥ (y - 2)²

- Take √ for both sides

∴ 1 ≥ y - 2 ≥ -1

- Add 2 for both sides

∴ 3 ≥ y ≥ 1

∴ The domain is 1 ≤ y ≤ 3

- In the function y = ± $\sqrt{1-x^{2}}+2$

∵ $\sqrt{1-x^{2}}$ ≥ 0

∴ 1 - x² ≥ 0

- Add x² for both sides

∴ 1 ≥ x²

- Take √ for both sides

∴ 1 ≥ x ≥ -1

∴ The domain is -1 ≤ x ≤ 1

* The graphs of these two function are half circle with center (0 , 2)

* All of the points on the circle that have distance 1 from point (0 , 2)

8 0

3 years ago

Write a linear equation that has m=-4 and passes through (5,9)!

sladkih [1.3K]

Answer:

$y=-4x+29$

Step-by-step explanation:

Using point-slope form,

$y-9=-4(x-5) \\ \\ y-9=-4x+20 \\ \\ y=-4x+29$

4 0

1 year ago