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3 years ago

Solve for x 3x−8≤23 AND −4x+26≥6

Mathematics

1 answer:

Nady [450]3 years ago

5 0

Answer:

Step-by-step explanation:

Ok so the first one is X<31/3

And the second one is X>-5

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Problem referred below <br> please help

zaharov [31]

Answer:

Step-by-step explanation:

Perimeter = 2l + 2w

57x2 = 114

234 - 114 = 120

120 / 2 = 60

6 0

3 years ago

Find the slope of the line that passes through the points (-19, -4) and (13, -17).

Tasya [4]

Answer:

m = $\frac{-13}{32}$

Step-by-step explanation:

Two point slope formula = $\frac{y_{2} - y_{1} }{x_{2} - x_{1} }$

$\frac{-17 + 4}{13 + 19} = \frac{-13}{32}$

7 0

3 years ago

Read 2 more answers

Calculate the measure of segment KL<br><br><br> HELP PLS

iVinArrow [24]

10x+3 = 3x+24

10x-3x= 24-3

7x=21

X= 21/7

Final answer:

X=3

I’m not so sure of my answer but wish you the best and good luck!!

5 0

3 years ago

Please, I need help with this!! :(

hram777 [196]

PQS = 40 because if you look at the image above it half equals 20 and 20+20=40

4 0

3 years ago

Expand the given power by using Pascal’s triangle. (9a - 10b)^6

xxMikexx [17]

Answer:

$531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6$

Step-by-step explanation:

1 n=0

1 1 n=1

1 2 1 n=2

1 3 3 1 n=3

1 4 6 4 1 n=4

1 5 10 10 5 1 n=5

1 6 15 20 15 6 1 n=6

This is where n is the exponent in

$(x+y)^n$ .

$(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6$

Now we want to expand:

$(9a-10b)^6$ or we we can rewrite as $(9a+(-10b))^6$ .

Let's replace $x$ with $(9a)$ and $y$ with $(-10b)$ in the expansion:

$(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6$

$((9a)+(-10b))^6$

$=1(9a)^6+6(9a)^5(-10b)+15(9a)^4(-10b)^2+20(9a)^3(-10b)^3+15(9a)^2(-10b)^4+6(9a)(-10b)^5+1(-10b)^6$

Let's simplify a bit:

$=9^6a^6-60(9)^5a^5b+15(-10)^2(9)^4a^4b^2+20(9)^3(-10)^3a^3b^3+15(9)^2(-10)^4a^2b^4+6(9)(-10)^5ab^5+(-10)^6b^6$

$=531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6$

8 0

3 years ago