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Flura [38]
3 years ago
7

Camila comprou um quilo de bolo de morango e dois quilos de bolo de chocalate por R$ 72,00 se o quilo do bolo de morango custa R

$ 18,00 qual é o valor do quilo do bolo de chocolate?
Mathematics
1 answer:
notka56 [123]3 years ago
4 0

Answer:

R$ 27,00

Step-by-step explanation:

R $ 72,00 = Um bolo de morango + dois quilos de bolo de chocalate

Um bolo de morango = R$ 18,00

R $ 72,00 = R$ 18,00 + Dois quilos de bolo de chocalate

Dois quilos de bolo de chocalate = R$72,00 - R$18,00

= R$54,00

Dois (2) quilos de bolo de chocalate = R$54,00

Um (1) quilo de bolo de chocalate = x

2x = R$ 54,00

x = R$ 54,00/2

x = R$ 27,00

Um quilo do bolo de chocolate = R$27,00

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3 years ago
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3 years ago
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Answer:

x=1

y=2

Step-by-step explanation:

y=x^2+3x-2 , y+3=5x

Replace all occurrences of y in y+3=5x with x^2+3x-2.

(x^2+3x-2)+3=5x

y=x^2+3x-2

Add -2 and 3.

x^2+3x+1=5x

y=x^2+3x-2

Subtract 5x from both sides of the <u>equation.</u>

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Subtract 5x from 3x.

x^2-2x+1=0

y=x^2+3x-2

Rewrite 1 as 1^2.

x^2-2x+1^2=0

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Check that the middle <u>term</u> is two times the <u>product</u> of the numbers being squared in the first <u>term</u> and third <u>term</u>.

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y=x^2+3x-2

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Add 1 to both sides of the <u>equation</u>.

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3 0
3 years ago
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Answer:

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Step-by-step explanation:

Well you have the right girl! *In honors geometry you can trust me!

Ok first thing...We already know

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san4es73 [151]

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