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yKpoI14uk [10]
3 years ago
14

John predicts his football team will score 67 points in the next game. If John's team actually scored 42 points, what was John's

percent error? Round your answer to the nearest tenth of a percent.
Mathematics
1 answer:
dolphi86 [110]3 years ago
8 0

Answer:

The error percentage was 59.5%

Step-by-step explanation:

John predicts his football team will score 67 points in the next game.

Prediction score = 67

But John's team actually scored 42 points.

Actual scored = 42

We need to find the error percentage of John's using formula.

\%=\dfrac{\text{|Prediction-exact|}}{exact}\times 100

\%=\dfrac{\text{|67-42|}}{42}\times 100

Percentage error =\dfrac{25}{42}\times 100

                             =59.52\%

We need to round off to nearest tenth.

Hence, The percentage error was 59.5%

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