If g (x) = 2x + 2, find g (a + h) - g a. . a. 2h b. 2h + 4 c. h + 2

2 answers:

6 0

G(x) = 2x + 2

g(a + h) - g(a) = 2(a+h) + 2 - (2(a) + 2)

g(a + h) - g(a) = 2a + 2h + 2 - 2a - 2

g(a + h) - g(a) = 2h + 2 - 2

g(a + h) - g(a) = 2h

Your final answer is a. 2h.

Maksim231197 [3]2 years ago

5 0

G(a+h)=2(a+h)+2=2a+2h+2

g(a)=2a+2

Subtracting gives 2a+2h+2-2a-2=2h. A is the correct answer.

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Answer:

$\dfrac{4}{5}$

Step-by-step explanation:

We are given 2 fractional numbers:

$1.\ \dfrac{2}4\\2.\ \dfrac{5}8$

We have to use fraction strips to compare to the fractional numbers.

Let we are Comparing $\frac{2}{4}$ with the length of $x$ number of $\frac{1}4$ sections.

i.e.

$\dfrac{2}{4} = x \times \dfrac{1}{4}\\\Rightarrow x = \dfrac{2 \times 4}{4}\\\Rightarrow x = 2$

Let we are Comparing $\frac{5}{8}$ with the length of $y$ number of $\frac{1}8$ sections.

i.e.

$\dfrac{5}{8} = y \times \dfrac{1}{8}\\\Rightarrow y = \dfrac{5 \times 8}{8}\\\Rightarrow y = 5$

Now, let us have a look at 3rd part of question:

The sections of 2/4 is _____ the length of 5/8. Therefore, 2/4 < 5/8

Let the answer be $z$ .

So, the equation becomes:

$\dfrac{2}{4} = z \times \dfrac{5}{8}\\\Rightarrow z = \dfrac{2 \times 8}{4 \times 5}\\\Rightarrow z = \dfrac{2 \times 2}{5}\\\Rightarrow z = \dfrac{4}{5}$